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\(\Rightarrow\frac{1,35}{0,2}=\frac{1,25}{0,1x}\)
=> 1,35.0,1x=0,2.1,25
=> 0,135x=0,25
=> x=0,25:0,135
=> x=50/27
a: \(\Leftrightarrow x^2=900\)
=>x=30 hoặc x=-30
b: \(\Leftrightarrow\dfrac{2}{3}:\left(-0.1x\right)=\dfrac{4}{3}:\dfrac{-2}{25}=-\dfrac{4}{3}\cdot\dfrac{25}{2}=-\dfrac{100}{6}=\dfrac{-50}{3}\)
=>0,1x=2/3:50/3=2/3x3/50=1/25
=>1/10x=1/25
hay x=1/25:1/10=10/25=2/5
d: \(\Leftrightarrow x^2=\dfrac{144}{25}\)
=>x=12/5 hoặc x=-12/5
x + x : 0,2 = 1,35
x * 1 + x * 5 = 1,35
x * ( 1 + 5 ) = 1,35
x * 6 = 1,35
x = 1,35 : 6
x = 0,225
hok tốt nha ^_^
a. \(\dfrac{2x}{3}:\dfrac{1}{5}=1\dfrac{1}{3}:\dfrac{1}{4}\Rightarrow\dfrac{2x}{3}\cdot\dfrac{1}{4}=\dfrac{1}{5}\cdot1\dfrac{1}{3}\Rightarrow\dfrac{2x}{3}=\dfrac{1}{5}\cdot1\dfrac{1}{3}:\dfrac{1}{4}=\dfrac{16}{15}\Rightarrow2x=\dfrac{16}{15}\cdot3=\dfrac{16}{5}\Rightarrow x=\dfrac{16}{5}:2=\dfrac{8}{5}\)
Vậy \(x=\dfrac{8}{5}\)
b. \(1,35:0,2=1,25:0,1x\Rightarrow1,35\cdot0,1x=0,2\cdot1,25\Rightarrow0,1x=\dfrac{0,2\cdot1,25}{1,35}=\dfrac{5}{27}\Rightarrow x=\dfrac{5}{27}:0,1=\dfrac{50}{27}\)
Vậy \(x=\dfrac{50}{27}\)
c. \(2:1\dfrac{1}{4}=\dfrac{1}{2}:2x\Rightarrow2\cdot\dfrac{4}{5}=\dfrac{1}{2}\cdot\dfrac{1}{2}\cdot x\Rightarrow\dfrac{8}{5}=\dfrac{1}{4}x\Rightarrow x=\dfrac{8}{5}:\dfrac{1}{4}=\dfrac{32}{5}\)
Vậy \(x=\dfrac{32}{5}\)
\(a,\Rightarrow\left[{}\begin{matrix}x-\dfrac{2}{3}=\dfrac{5}{4}\\\dfrac{2}{3}-x=\dfrac{5}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{12}\\x=-\dfrac{7}{12}\end{matrix}\right.\\ b,\Rightarrow0,1x\cdot1,35=0,2\cdot1,25=0,25\\ \Rightarrow0,135x=0,25\Rightarrow x=\dfrac{50}{27}\\ c,ĐK:x\ge0\\ PT\Leftrightarrow-2\sqrt{x}=-6\Leftrightarrow x=9\left(tm\right)\\ d,\Leftrightarrow3^{x+2}\cdot2^{x-1}=\left(3^2\cdot2^2\right)^3=3^6\cdot2^6\\ \Leftrightarrow\left\{{}\begin{matrix}x+2=6\\x-1=6\end{matrix}\right.\Leftrightarrow x\in\varnothing\)
ta có: 1,35/0,2 = 6,75
=> 1,25/0,1.x = 6,75
0,1.x = 5/27
x = 50/27
x=50/27