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11+12+13+14+15+16+17+18+19+...+89+88+87+86+85+84+83+82
=( 11 + 89 )+(12+88)+(13+87)+(14+86)+(15+85)+(16+84)+(17+83)+(18+82)+19
=100+100+100+100+100+100+100+100+19
=800+19
=819
Ta có :
(13+85):3+1=33.7777777777777777777777777777777.............
a) \(39\times118+29\times82\)
\(=39\times2\times59+29\times2\times41\)
\(=2\times\left(39\times59+29\times41\right)\)
\(=2\times\left(2301+1189\right)\)
\(=2\times3490\)
\(=6980\)
b) \(37\times39+78\times14-13\times85-52\times55\)
\(=37\times3\times13+6\times13\times14+13\times85-4\times13\times55\)
\(=13\times\left(37\times3+6\times14+85-4\times55\right)\)
\(=13\times\left(111+84+85-220\right)\)
\(=13\times\left(280-220\right)\)
\(=13\times60\)
\(=780\)
c) \(368:16+752:16+480:16\)
\(=\left(368+752+480\right):16\)
\(=\left(1120+480\right):16\)
\(=1600:16\)
\(=100\)
d) \(5\times11\times18+9\times31\times10+4\times29\times45\)
\(=5\times11\times9\times2+9\times31\times10+2\times2\times29\times5\times9\)
\(=10\times9\times11+10\times9\times31+10\times29\times2\times9\)
\(=90\times11+90\times31+90\times29\times2\)
\(=90\times\left(11+31+29\times2\right)\)
\(=90\times\left(42+58\right)\)
\(=90\times100\)
\(=9000\)
1. -86 + ( -14)
= -86 - 14
= -100
2. 123 + ( -36)
= 123 - 36
= 87
3. ( -44) - ( -66)
= -44 + 66
= 22
4. -82 + (-28)
= -82 - 28
= -110
5. 83 + ( -17)
= 83 - 17
= 66
Các bài khác làm tương tự nha bạn
1/ (-86)+(-14)=-86-14=-100
2/123+(-36)=123-36=87
3/(-44)-(-66)=-44+66=22
4/-82+(-28)=-82-28=-110
5/83+(-17)=83-17=66
6/(-83)-33=(-83)+(-33)=-116
7/ 73+(-24)=73-24=49
8/84+(-48)=84-48=36
9/-72-82=-72+(-82)=-154
10/-97-82=-97+(-82)=-179
11/19+(-92)=19-92=-73
12/38-28=10
13/13+(-27)=13-27=-14
14/-85+29=-85-(-29)=-114
15/-84-(-27)=-84+27=-57
16/-23+78=-23-(-78)=-101
17/93+(-29)=93-29=64
18/-74-83=-74+(-83)=-157
19/-183+83=-183-(-83)=-266
20/849-(-3832)=849+3832=4681
Có gì sai mong bạn sửa giúp mình nhé!
Giải:
Đặt \(A=\dfrac{6}{4.7}+\dfrac{6}{7.10}+\dfrac{6}{10.13}+...+\dfrac{6}{82.85}\)
\(\dfrac{1}{2}A=\dfrac{3}{4.7}+\dfrac{3}{7.10}+\dfrac{3}{10.13}+...+\dfrac{3}{82.85}\)
\(\dfrac{1}{2}A=\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+...+\dfrac{1}{82}-\dfrac{1}{85}\)
\(\dfrac{1}{2}A=\dfrac{1}{4}-\dfrac{1}{85}\)
\(\dfrac{1}{2}A=\dfrac{81}{340}\)
\(\Rightarrow A=\dfrac{81}{340}:\dfrac{1}{2}\)
\(A=\dfrac{81}{170}\)
a) 1 - 2 + 3 - 4 + 5 - 6 + ... + 97 - 98 + 99 - 100 + 101 (có 101 số; 101 chia 2 dư 1)
= (1 - 2) + (3 - 4) + (5 - 6) + ... + (97 - 98) + (99 - 100) + 101 (có 50 nhóm và dư 1 số)
= -1 + (-1) + (-1) + ... + (-1) + (-1) + 101
= -1.50 + 101
= -50 + 101
= 51
2 câu c` lại cx chia thành nhóm r` lm tương tự
1 - 2 + 3 - 4 + ........ + 99 - 100 + 101
= ( 1 - 2) + ( 3 - 4 ) + ..... + ( 99 -100 ) + 101 ( 50 nhóm )
= - 1 + ( - 1 ) + ...... + ( -1) + 101 ( 50 số -1 )
= - 1 . 50 + 101
= 50 + 101
= 151
\(2575+37-2576-29\)
\(=2612-2576-29\)
\(=36-29=7\)'
\(35+35+36+37-14-15-16-17\)
\(=70+\left(36-16\right)+\left(37-17\right)-14-15\)
\(=70+20+20-14-15\)
\(=90+6-15\)
\(=96-15=81\)
\(13\cdot\left(-12\right)+87.\left(-12\right)\)
\(=\left(-12\right)\cdot\left(13+87\right)\)
\(=\left(-12\right)\cdot100=-1200\)
\(26\cdot17+17\cdot74\)
\(=\left(26+74\right)\cdot17\)
\(=100\cdot17=1700\)
\(25\cdot\left(-18\right)+25\left(-82\right)\)
\(=25\cdot\left[\left(-18\right)+\left(-82\right)\right]\)
\(=25\cdot\left(-100\right)=\left(-2500\right)\)
\(25+37-48-25-37\)
\(=\left(25-25\right)+\left(37-37\right)-48\)
\(=0+0-48\)
\(=0-48=\left(-48\right)\)
\(\left(-16\right)+24+16-34\)
\(=\left[\left(-16\right)+16\right]+\left(24-34\right)\)
\(=0+\left(-10\right)=\left(-10\right)\)
Số số hạng: (85 - 13) : 3 + 1 = 25
Tổng: (85 + 13) x 25 : 2 = 1225
Đáp số: 1225