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2 tháng 5 2019

\(\frac{3}{2}\cdot\frac{1}{3}+\frac{8}{5}:4\\ =\frac{1}{2}+\frac{8}{5\cdot4}\\ =\frac{1}{2}+\frac{2}{5}\\ =\frac{5}{10}+\frac{4}{10}\\ =\frac{9}{10}\)

2 tháng 5 2019

3/2.1/3+8/5:4

=1/2+8/5.1/4

=1/2+2/5

=5/10+4/10

=9/10

NHỚ TICK MÌNH NHÉ

11 tháng 2 2023

\(a,\dfrac{1}{2}-\dfrac{1}{3}-\left(-\dfrac{5}{4}\right)=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{5}{4}=\dfrac{1\times6-1\times4+5\times3}{12}=\dfrac{6-4+15}{12}=\dfrac{17}{12}\\ b,\dfrac{5}{4}-\dfrac{1}{2}-\dfrac{7}{8}=\dfrac{5\times2-1\times4-7}{8}=\dfrac{10-4-7}{8}=-\dfrac{1}{8}\\ c,\dfrac{1}{5}-\dfrac{1}{2}+\dfrac{9}{10}=\dfrac{1\times2-1\times5+9}{10}=\dfrac{2-5+9}{10}=\dfrac{6}{10}=\dfrac{3}{5}\\ d,\dfrac{5}{4}-\dfrac{1}{3}+\dfrac{7}{6}=\dfrac{5\times3-1\times4+7\times2}{12}=\dfrac{15-4+14}{12}=\dfrac{25}{12}\)

11 tháng 2 2023

`1/2+(-1/3)-(-5/4)`

`=1/2-1/3+5/4`

`=3/6-2/6+5/4`

`=1/6+5/4`

`=2/12+15/12`

`=17/12`

__

`5/4-1/2+(-7/8)`

`=5/4-1/2-7/8`

`=10/8-4/8-7/8`

`=6/8-7/8`

`=-1/8`

__

`1/5-1/2+9/10`

`=2/10-5/10+9/10`

`=-3/10+9/10`

`=6/10`

`=3/5`

__

`5/4-1/3+7/6`

`=15/12-4/12+14/12`

`=11/12+14/12`

`=25/12`

`#lv`

8 tháng 9 2020

a) \(1,25^2-0,5^2+3,25^3\)

\(=\left(\frac{5}{4}\right)^2-\left(\frac{1}{2}\right)^2+\left(\frac{13}{4}\right)^3\)

\(=\frac{25}{16}-\frac{1}{4}+\frac{2197}{64}\)

\(=\frac{2281}{64}\)

b) \(1,2+2,4^2-\left(3\frac{1}{2}\right)^2\)

\(=\frac{6}{5}+\left(\frac{12}{5}\right)^2-\left(\frac{7}{2}\right)^2\)

\(=\frac{6}{5}+\frac{144}{25}-\frac{49}{4}\)

\(=\frac{-529}{100}\)

31 tháng 3 2019

          Q = 14 . 29 + 14 . 71 + ( 1 + 2 + 3 + ... + 99)(199199 . 198 - 198198 . 199)

= 14 . ( 29 + 71 ) + ( 1 + 2 + ... + 99)( 199 . 1001 . 198 - 198 . 1001 . 199 )

= 14 . 100 + ( 1  + 2 + ... + 99) . 0

= 1400 + 0

= 1400

31 tháng 3 2019

\(Q=14.29+14.71+\left(1+2+3+4+....+99\right).\left(199199.198-198198.199\right)\)

\(=14.\left(29+71\right)+\left(1+2+3+4+..+99\right).\left(199.101.198-198.1001.199\right)\)

\(=14.100+\left(1+2+3+4+...+99\right).0\)

\(=1400+0\)

\(=1400\)

17 tháng 9 2021

= 93809060 nhé bạn

17 tháng 9 2021

cảm ơn

11 tháng 2 2023

`#lv`

`-2/5+(-7/10)-9/6`

`=-2/5-7/10-9/6`

`=-4/10-7/10-9/6`

`=-11/10-3/2`

`=-11/10-15/10`

`=-26/10`

`=-13/5`

__

`1/2+(-2/5)-(-2/3)`

`=1/2-2/5+2/3`

`=5/10-4/10+2/3`

`=1/10+2/3`

`=3/30+20/30`

`=23/30`

__

`5/3-3/4+7/6`

`=20/12-9/12+14/12`

`=11/12+14/12`

`=25/12`

__

`-1/5+5/3-3/2`

`=-3/15+25/15-3/2`

`=22/15-3/2`

`=44/30-45/30`

`=-1/30`

__

`1/4-7/8+(-9/10)`

`=2/8-7/8-9/10`

`=-5/8-9/10`

`=-25/40-36/40`

`=-61/40`

__

`5/4+1/2+(-7/12)`

`=15/12+6/12-7/12`

`=21/12-7/12`

`=14/12`

`=7/6`

__

`-5/8-1/3+(-7/6)`

`=-5/8-1/3-7/6`

`=-15/24-8/24-28/24`

`=-52/24`

`=-13/6`

__

`-3/4-7/10+(-5/6)`

`=-3/4-7/10-5/6`

`=-45/60-42/60-50/60`

`=-137/60`

11 tháng 2 2023

Bài làm

a, (-2/5) + (-7/10) - 9/6 =(-12/30) + (-21/30) - 45/30=(-33/30) - 45/30 = (-78/30)

b,1/2 + (-2/5) - (-2/3) = 15/30 + (-12/30) - (-20/30) = 3/30 - (-20/30) = 23/30

c,5/3 - 3/4 + 7/6 = 40/24 - 18/24 + 28/24 = 22/24 + 28/24 = 50/24 = 25/12

d, (-1/5) + 5/3 - 3/2 = (-6/30) + 50/30 - 45/30 = 44/30 - 45/30 = (-1/30)

e, 1/4 - 7/8 + (-9/10) = 10/40 - 35/40 - 36/40 = (-25/40) - 36/40 = (-61/40)

f, 5/4 +1/2 + (-7/12) = 15/12 + 6/12 - 7/12 = 21/12 - 7/12 = 14/127/6

g,(-5/8) -1/3 + (-7/6) = (-15/24) - 8/24 - 28/24 = (-23/24) - 28/24 = (-51/24) 

k,(-3/4) - 7/10 + (-5/6) = (-45/60) - 42/60 - 50/60 = (-87/60) - 50/60 = (-137/60)

chúc bn học tốt nha

sai thì mn góp ý giúp mk

 

8 tháng 11 2023

\(B=2^2+2^3+2^4+...+2^{121}\\=(2^2+2^3)+(2^4+2^5)+(2^6+2^7)+...+(2^{120}+2^{121})\\=2^2\cdot(1+2)+2^4\cdot(1+2)+2^6\cdot(1+2)+...+2^{120}\cdot(1+2)\\=2^2\cdot3+2^4\cdot3+2^6\cdot3+...+2^{120}\cdot3\\=3\cdot(2^2+2^4+2^6+...+2^{120})\)

Vì \(3\cdot(2^2+2^4+2^6+...+2^{120})\vdots3\)

nên \(B\vdots3\)

a, \(A=1+\frac{1}{2^2}+\frac{1}{3^2}+...+\frac{1}{50^2}\)

\(A< 1+\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{49.100}\)

\(A< 1+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{49}-\frac{1}{50}\)

\(A< 2-\frac{1}{50}\)

\(A< 2\)

b, \(B=2+2^2+2^3+...+2^{30}\)

Ta có :\(B=\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{29}+2^{30}\right)\)

\(B=2\left(1+2\right)+2^3\left(1+2\right)+...+2^{29}\left(1+2\right)\)

\(B=2.3+2^3.3+...+2^{29}.3\)

\(B=3\left(2+2^3+...+2^{29}\right)\)chia hết cho 3(1)

Lại có\(B=\left(2+2^2+2^4\right)+...+\left(2^{28}+2^{29}+2^{30}\right)\)

\(B=2\left(1+2+4\right)+...+2^{28}\left(1+2+4\right)\)

\(B=2.7+...+2^{28}.7\)

\(B=7\left(2+...+2^{29}\right)\) chia hết cho 7 (2) 

Mà (3,7)=1 (3) 

Từ (1)(2)(3) => B chia hết cho 21

16 tháng 3 2020

1)-(-3)3-(2x+1)3=152

    27-(2x+1)3=152

          (2x+1)3=27-152

          (2x+1)3=-125

          (2x+1)3=(-5)3

           2x+1=-5

           2x=-4

             x=-4:2

             x=-2

Vậy x=-2