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\(=25\cdot75-25\cdot49+75\cdot\left(49-25\right)\)
\(=25\cdot75-25\cdot49+75\cdot49-75\cdot25\)
=49x50=2450
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a. 15 . 12 - 3 . 5 . 10
= 15 . 12 - 15 . 10
= 15 . (12 - 10)
= 15 . 2
= 30
b. 45 – 9.(13 + 5)
= 45 – (9 . 13 + 9 . 5)
= 45 – 9 . 13 - 9 . 5
= 45 – 117 - 45
= 45 - 45 - 117
= 0 - 117
= -117
c. 29. (19 – 13) – 19.(29 -13)
= 29 . 19 – 29 . 13 – (19 . 29 - 19 . 13)
= 29 . 19 – 29 . 13 – 19 . 29 + 19 . 13
= 29 . 19 - 19 . 29 - 29 . 13 + 19 . 13
= (29 . 19 - 19 . 29) - (29 . 13 - 19 . 13)
= 0 - 13 . (29 - 19)
= 0 - 13 . 10
= 0 - 130
= -130
d. 25 - (-75) + 32 – (32 + 75)
= 25 + 75 + 32 – 32 - 75
= (32 – 32) + (75 - 75) + 25
= 0 + 0 + 25
= 25
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214+[120-(214+120)]
=214+120-(214+120)
=214+120-214-120
=(214-214)+(120-120)
=0+0=0
(-321)-[(-321+35)-235]
=(-321)-(-321+35)+235
=(-321)+(-321-35)-235
=-321-(-321) +(235-35)
=0+200
=200
(18+29)+(158-29-18)
=18+29+158-29-18
=(18-18)+(29-29)+158
=0+0+158
=158
(13-135+49)-(13+49)
=13-135+49-13-49
=(13-13)+(49-49)-135
=0-135
= -135
25+(-13+8)
=25+(-5)
=20
7+(-12+43)-[2+(19-34)]
=7+31-[2+(-15)]
=7+31-(-13)
=38+(-13)
=25
nhiều quá, mk phụ chút thôi
1.a)214+[120-(214+120)=214+120-214-120=(214-214)+(120-120)=0+0=0
b)(-321)-[(-321+35)-235]=(-321)+321-35+235=[(-321)+321]+(235-35)=0+200=200
2.a)(18+29)+(158-29-18)=18+29+158-29-18=(18-18)+(29-29)+158=0+0+158=158
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45 ( 75 - 13 ) + 75 ( 45 - 13 )
= 45 x ( 75 - 13 ) + 45 ( 75 - 13 )
=45 x ( 75 - 13 )
= 45 x 62
= 2790
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1.
x + 25 + ( -17)+63
=x+25-17+63
(-75)-(p+20)+95
=-75-p-20+95
2.
(18+29)+(158-18-29)
=18+29+158-18-29
=(29-29)+(18-18)+158
=158
(12-135+49)-(13+49)
=12-135+49-13-49
=-136
hình như câu cuối là 12 chứ k phải 13
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a)29.(19-`13)-19.(29-13)
=29.6-19.16
=174-304
=-130
b) 27.75+25.75-150
=(27+25).75-150
=52.75-150
=3900-150
=3750
b,27.75+25.75-150=27.75+25.75-2.75=75.(27+25-2)=75.50=3750
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b. 7 + (-12 + 43) - [2 + (19 - 34)]
= 7+31- [2+(-15)]
= 7+31-(-13)
= 51
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Trl :
\(13.75+25.13-120\)
\(=13.\left(75+25\right)-120\)
\(=13.100-120\)
\(=1300-120\)
\(=1180\)
= 13. (75+25) - 120
= 13. 100 - 120
= 1300 - 120
= 1180