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\(a,\frac{7}{3}x+5=\frac{9}{6}x-7\)
\(\frac{7}{3}x-\frac{9}{6}x=-7-5\)
\(\left(\frac{7}{3}-\frac{9}{6}\right).x=-12\)
\(\frac{5}{6}.x=-12\)
\(x=\left(-12\right):\frac{5}{6}\)
\(x=-\frac{72}{5}\)
\(b,3x+\frac{6}{4}=5-\frac{7x}{6}\)
\(3x+\frac{7x}{6}=5-\frac{6}{4}\)
\(\left(3+\frac{7}{6}\right).x=\frac{7}{2}\)
\(\frac{25}{6}.x=\frac{7}{2}\)
\(x=\frac{7}{2}:\frac{25}{6}\)
\(x=\frac{21}{25}\)
\(c,\frac{12}{5}x+6=\frac{17}{3}x+12\)
\(\frac{12}{5}x-\frac{17}{3}x=12-6\)
\(-\frac{49}{15}x=6\)
\(x=6:\left(-\frac{49}{15}\right)\)
\(x=-\frac{90}{49}\)
\(d,6\left(3x+7\right)=12\left(2x-4\right)\)
\(18x+42=24x-48\)
\(18x-24x=-48-42\)
\(-6x=-90\)
\(x=15\)
\(e,13\left(2x-9\right)=8\left(3x-13\right)\)
\(26x-117=24x-104\)
\(26x-24x=-104+117\)
\(2x=13\)
\(x=\frac{13}{2}\)
3x - 2x = 13 - 19
x = -6
Vậy x = -6
3x + 7 = 4 - 3x
3x + 3x = 7 - 4
6x = 3
x = 3 : 6
x = \(\frac{1}{2}\)
Vậy x = \(\frac{1}{2}\)
5 ( x + 1 ) -3 x = x + 9
5 . x + 5 . 1 - 3x = x + 9
5x + 5 - 3x = x + 9
5x - x - 3x + 5 = 9
4x - 3x = 9 - 5
x = 4
Vậy x = 4
A) 3x-2x=13-19
=>. x=-6
Vậy x=-6
b)3x+7=4-3x
=>3x+3x=4-7
=>. 6x=-3
=>. x=-3/6
Vậy x=-3/6
c)5(x+1)-3x=x+9
=>5x+5-3x=x+9
=>. 5x-3x-x=9-5
=>. x=4
Vậy x=4
Chúc bạn học tốt nhé!
Bài 1:
a) Ta có: \(82-7\left(3x-4\right)=47\)
\(\Leftrightarrow82-21x+28-47=0\)
\(\Leftrightarrow-21x+63=0\)
\(\Leftrightarrow-21x=-63\)
hay x=3(nhận)
Vậy: x=3
b) Ta có: \(97+4\left(5x-7\right)=129\)
\(\Leftrightarrow97+20x-28-129=0\)
\(\Leftrightarrow20x-60=0\)
\(\Leftrightarrow20x=60\)
hay x=3(nhận)
Vậy: x=3
c) Ta có: \(\left(7x-13\right)\cdot27-12=15\)
\(\Leftrightarrow189x-351-12-15=0\)
\(\Leftrightarrow189x-378=0\)
\(\Leftrightarrow189x=378\)
hay x=2(nhận)
Vậy: x=2
d) Ta có: \(\left(2x+3\right)\cdot13+23=140\)
\(\Leftrightarrow26x+39+23-140=0\)
\(\Leftrightarrow26x-78=0\)
\(\Leftrightarrow26x=78\)
hay x=3(nhận)
Vậy: x=3
đ) Ta có: \(52x+8x-5x=70\)
\(\Leftrightarrow55x=70\)
\(\Leftrightarrow x=\frac{70}{55}\)(loại)
Vậy: x∈∅
e) Ta có: \(19x-3x-x=60\)
\(\Leftrightarrow15x=60\)
hay x=4(nhận)
Vậy: x=4
g) Ta có: \(7\left(3x+1\right)-5\left(3x+1\right)=74\)
\(\Leftrightarrow2\left(3x+1\right)=74\)
\(\Leftrightarrow3x+1=37\)
\(\Leftrightarrow3x=36\)
hay x=12(nhận)
Vậy: x=12
h) Ta có: \(5\left(3x-1\right)+7\left(3x-1\right)=96\)
\(\Leftrightarrow12\left(3x-1\right)=96\)
\(\Leftrightarrow3x-1=8\)
\(\Leftrightarrow3x=9\)
hay x=3(nhận)
Vậy: x=3
bn đừng nói ai xin lỗi với mình nữa nhé ! trả lời nick mình rồi mình sẽ nói cho
a, \(0,5x-\frac{2}{3}x=\frac{7}{12}\)
=> \(x\left(0,5-\frac{2}{3}\right)=\frac{7}{12}\)
=>\(\frac{-1}{6}x=\frac{7}{12}\)=> \(x=\frac{7}{12}:\frac{-1}{6}=\frac{-7}{2}\)
b, \(x:\frac{13}{3}=-2,5\)
=>\(x=\left(-2,5\right):\frac{13}{3}=\frac{-7,5}{13}\)
c, \(5,5x=\frac{13}{15}\)
=>\(x=\frac{13}{15}:5,5=\frac{13}{82,5}\)
d, \(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
=>\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}:\left(-4\right)=\frac{1}{7}\)
=>\(\frac{3x}{7}=\frac{1}{7}-1=\frac{-6}{7}\)
=>\(3x=-6\)
=> \(x=\left(-6\right):3=-3\)
a: =>1/2x-2/3x=7/12
=>-1/6x=7/12
hay x=-7/2
b: \(\Leftrightarrow x=-\dfrac{5}{2}\cdot\dfrac{13}{3}=\dfrac{-65}{6}\)
c: =>x=13/15:11/2=26/165
d: =>3/7x+1=1/7
=>3/7x=-6/7
hay x=-2
ta có : (13 - 3x)^7 x 0 = (13-3x)^4 x 0 => (13 - 3x)^7 x 0 - (13-3x)^4 x 0 = 0 = 0 x [(13 - 3x)^7 - (13-3x)^4]
vì : 0 x [(13 - 3x)^7 - (13-3x)^4] và (13 - 3x)^7 x 0 = (13-3x)^4 => (13 - 3^x) x 0 = (13 - 3)^x
kết luận : (13 - 3x)^7 = (13-3x)^4