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\(\left(\frac{15}{8}-\frac{9}{13}\right)+\left(\frac{22}{13}-\frac{5}{8}\right)\)
\(=\left(\frac{15}{8}-\frac{5}{8}\right)+\left(\frac{22}{13}-\frac{9}{13}\right)\)
\(=\frac{10}{8}+\frac{13}{8}\)
\(=\frac{23}{8}\)
(15/8-9/13)+(22/13-5/8)= (15/8-5/8)-(9/13-22/13)=10/8-(-1)=9/4)

7/13 x 7/15 - 5/12 x 7/13 + 7/13 x 8/15 =7/13x(7/15-5/12+8/15)=7/13x7/12=49/156
12/13×8/15×7/9=........................
........................

a, 13 - 18 - ( - 42 ) -1 5 = 22
c,(-8 ) ^ 3 : ( - 8 ) ^ 2 +8 = 0

a/ x - ( 25 - x) = x - 15
=> x - 25 + x = x - 15
=> 2x - x = -15 + 25
=> x = 10
b/ x - 8 = -13 - 8
=> x = -13 - 8 + 8 = -13
c/ x - (-15) = 5 - (-19)
=> x + 15 = 5 + 19 => x = 5 + 19 - 15 = 9
d/ (x + 35) = 2x + 15 + (13 - 4)
=> x + 35 = 2x + 15 + 13 - 4
=> x - 2x = 15 + 13 - 4 - 35
=> -x = -11 => x = 11
e/ 5 - 2x = 15-(-9) - 3x
=> 5 - 2x = 15 + 9 - 3x
=> -2x + 3x = 15 + 9 - 5
=> x = 19
g/ x + 135 = 3x - 15
=> x - 3x = -15 - 135
=> -2x = -150
=> x = -150/ - 2 = 75

a ) 13 - 18 - ( - 42 ) - 15
= 13 - 18 + 42 - 15
= -5 + 42 - 15
= 37 - 15
= 22

cái này dễ mak bn,hok lý thuyết ik,nhưng mk bt là bn bt lm bài này

a, \(7^{2019}=7^3.7^{2016}=343.\left(7^4\right)^{504}=343.\left(...1\right)^{504}=343.\left(...1\right)=\left(....3\right)\)
b, \(12^{2019}=12^3.12^{2016}=\left(...8\right).\left(12^4\right)^{504}=\left(...8\right).\left(...6\right)^{504}=\left(...8\right).\left(...6\right)=\left(...8\right)\)
c, \(11^8+12^8+13^8+14^8+15^8+16^8\)
\(=\left(...1\right)+\left(12^4\right)^2+\left(13^4\right)^2+\left(...5\right)+\left(...6\right)=\left(....1\right)+\left(....6\right)^2+\left(...1\right)^2+\left(...5\right)+\left(...6\right)\)
\(=\left(....1\right)+\left(....6\right)+\left(...1\right)+\left(...5\right)+\left(...6\right)=\left(...9\right)\)
d, \(11^{123}+13^{124}+15^{125}=\left(....1\right)+\left(13^4\right)^{31}+\left(....5\right)=\left(...1\right)+\left(...1\right)+\left(....5\right)=\left(...7\right)\)
\(a,7^{2019}=\left[7^3\right]^{673}=\overline{....}3^{673}=\overline{....3}\)
Vậy chữ số tận cùng của 72019 là 3
\(b,12^{2019}=\left[12^3\right]^{673}=\overline{....8}^{673}=\overline{....8}\)
Vậy chữ số tận cùng của 122019 là 8
Làm nốt

\(a,13-18-\left(-42\right)-15\)
\(=13-18+42-15\)
\(=\left(13-15\right)-\left(18+42\right)\)
\(=-2-60\)
\(=-62\)
\(b,369-4\left[\left(-5\right)+4.\left(-8\right)\right]\)
\(=369-4\left[\left(-5\right)+\left(-32\right)\right]\)
\(=369-4.\left(-37\right)\)
\(=369-\left(-148\right)\)
\(=369+148\)
\(=517\)
\(c,\left(-8\right)^3:\left(-8\right)^2+8\)
\(=-512:64+8\)
\(=-8+8\)
\(=0\)
\(d,\left(-12\right)\left(-13\right)+13.\left(-29\right)\)
\(=156+-377\)
\(=156-377\)
\(=-221\)

Tính:
1) -5 - (-12)+(-4)
=-5+12+(-4)
=7+(-4)
=3
2) - (-7) + (-14) - (-20)
=-7-(-20)
=-7+20
=13
3) (-13) - (-8) + (-15)
=-13+8+(-15)
=-5+(-15)
=-20
4) 17 - (-19) - (+25)
=17+19-25
=36-25
=11
5) - |-13| - (-8) + (-15)
=-13+8+(-15)
=21+(-15)
=6
[(-13)+(-15)]+(-8)
= [ -(13+15)]+(-8)
=( -28)+(-8)
= -(28+8)
= -36
[(-13) + (-15)] + (-8)
= (-28) + (-8)
= -36