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\(30-5x⋮x\)
\(\Leftrightarrow30-5x+5x⋮x\left(\text{vì: 5x chia hết cho x}\right)\)
\(\Rightarrow30⋮x\Rightarrow x\in\left\{-1;1;-2;2;-3;3;-5;5;-6;6;-10;10;-15;15;-30;30\right\}\)
a. \(158-x=-12\)
\(x=158+12\)
\(x=170\)
b. \(37+x=12\)
\(x=12-37\)
\(x=-25\)
c. \(2x-15=-47\)
\(2x=\left(-47\right)+15\)
\(x=\dfrac{\left(-32\right)}{2}\)
\(x=-16\)
d. \(\left(-5\right)^2-\left(5x-3\right)=43\)
\(25-\left(5x-3\right)=43\)
\(\left(5x-3\right)=25-43\)
\(5x=\left(-18\right)+3\)
\(x=\dfrac{\left(-15\right)}{5}=-3\)
e. \(\left|x-1\right|+\left(-5\right)=2\)
\(\left|x-1\right|=2-\left(-5\right)\)
\(\left|x-1\right|=7\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=7\\x-1=-7\end{matrix}\right.\Leftrightarrow}\left[{}\begin{matrix}x=8\\x=-6\end{matrix}\right.\)
f. \(\left|x+1\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
g. \(\left|x\right|=12\)
\(\Rightarrow x=\pm12\)
Câu h ko có x sao tìm
a) \(158-x=-12.\)
\(\Rightarrow x=158-\left(-12\right).\)
\(\Rightarrow x=158+12=170.\)
Vậy..........
b) \(37+x=12.\)
\(\Rightarrow x=12-37.\)
\(\Rightarrow x=-25.\)
Vậy..........
c) \(2x-15=-47.\)
\(\Rightarrow2x=-47+15.\)
\(\Rightarrow2x=-32.\)
\(\Rightarrow x=-\dfrac{32}{2}=-16.\)
Vậy..........
d) \(\left(-5\right)^2-\left(5x-3\right)=43.\)
\(\Rightarrow25-\left(5x-3\right)=43.\)
\(\Rightarrow5x-3=25-43.\)
\(\Rightarrow5x-3=-18.\)
\(\Rightarrow5x=-18+3.\)
\(\Rightarrow5x=-15.\)
\(\Rightarrow x=-\dfrac{15}{5}=3.\)
Vậy..........
e) \(\left|x-1\right|+\left(-5\right)=2.\)
\(\Rightarrow\left|x-1\right|=2-\left(-5\right).\)
\(\Rightarrow\left|x-1\right|=2+5.\)
\(\Rightarrow\left|x-1\right|=7.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=7\\x-1=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-6\end{matrix}\right..\)
Vậy..........
f) \(\left|x+1\right|=4\Leftrightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right..\)
Vậy..........
g) \(\left|x\right|=12\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-12\end{matrix}\right..\)
Vậy..........
\(\left(x-4\right).\left(x+12\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=0\\x+12=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-12\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x-4=0\\x+12=0\end{cases}\Rightarrow}\hept{\begin{cases}x=4\\x=-12\end{cases}}\)
a)4.(x+3)-(2x-12)=x-(-11+4)
4x+12-2x+12=x+11-4
2x+24=x+7
2x-x=-24+7
x=-17
b)-(4x-13)+(5x-4)=-3-(-15+7)
-4x+13+5x-4=-3+15-7
(-4x+5x)+13-4=12-7
x+9=5
x=-4
c)(5x-3)-(-2x+4)=6x-12
5x-3+2x-4=6x-12
5x+2x-6x=3+4-12
x=-5
d)(15x+20)-(9x-3)=5x-(-12)
15x+20-9x+3=5x+12
15x-9x-5x=-20-3+12
x=-11
e,(7x+14)+(3x-8)=-(-9x+3)
7x+14+3x-8=9x-3
7x+3x-9x=-14+8-3
x=-9
2x + 12 = 3(x - 7)
2x + 12 = 3x - 21
12 + 21 = 3x - 2x
33 = x
a)|1/2x|=3-2x
\(\frac{\left|x\right|}{2}=-\left(2x-3\right)\)
\(x=\frac{6}{5}\)
12+x=5x-20
x-5x=-20-12
-4x=-32
x=-32:(-4)
x=8
Vậy x = 8
Bạn ơi bạn nhìn lại đề bài là âm 12 nhé