Câu hỏi của nguyen thi thy

Question

(1/2)³:2+(-1/3)³.2-[(7/11)²⁰⁰⁹]⁰ = ?

Xuân · Accepted Answer

$\left(\frac{1}{2}\right)^3:2+\left(-\frac{1}{3}\right)^3.2-\left[\left(\frac{7}{11}\right)^{2009}\right]^0$

$=\frac{1}{8}:2-\frac{1}{27}.2-1$

$=\frac{1}{16}-\frac{2}{27}-1$

$=-\frac{437}{432}$ số xấu wá

Câu trả lời:

$\left(\frac{1}{2}\right)^3:2+\left(-\frac{1}{3}\right)^3.2-\left[\left(\frac{7}{11}\right)^{2009}\right]^0$

$=\frac{1}{8}:2-\frac{1}{27}.2-1$

$=\frac{1}{16}-\frac{2}{27}-1$

$=-\frac{437}{432}$ số xấu wá