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\(\frac{3}{5}\times\frac{6}{7}+\frac{3}{5}:7+\frac{6}{5}\)
\(=\frac{3}{5}\times\frac{6}{7}+\frac{3}{5}\times\frac{1}{7}+\frac{6}{5}\)
\(=\frac{3}{5}\times\left(\frac{6}{7}+\frac{1}{7}\right)+\frac{6}{5}\)
\(=\frac{3}{5}\times1+\frac{6}{5}\)
\(=\frac{3}{5}+\frac{6}{5}=\frac{9}{5}\)
~ Hok tốt ~
\(\frac{29}{12}:\frac{1}{2}-\frac{5}{12}:\frac{1}{2}-\frac{1}{2}\)
\(=\left(\frac{29}{12}-\frac{5}{12}\right):\frac{1}{2}-\frac{1}{2}\)
\(=2:\frac{1}{2}-\frac{1}{2}\)
\(=4-\frac{1}{2}=\frac{7}{2}\)
~ Hok tốt ~
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\(a:=\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+\left(\dfrac{1}{5}+\dfrac{2}{5}\right)\\ =1+\dfrac{3}{5}=1\dfrac{3}{5}\\ b:=\left(\dfrac{2}{7}+\dfrac{1}{7}\right)+\left(\dfrac{5}{14}+\dfrac{3}{14}\right)\\ =\dfrac{3}{7}+\dfrac{8}{14}\\ =\dfrac{3}{7}+\dfrac{4}{7}=1\)
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\(\frac{1}{2}\cdot\frac{18}{14}+\frac{1}{2}\cdot\frac{3}{14}-\frac{1}{2}\cdot\frac{7}{14}\)
\(=\frac{1}{2}\left(\frac{18}{14}+\frac{3}{14}-\frac{7}{14}\right)\)
\(=\frac{1}{2}\cdot1=\frac{1}{2}\)
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\(\left(2+\frac{2}{3}-\frac{1}{4}\right)\cdot\frac{1}{5}\)
\(=\left(\frac{24}{12}+\frac{8}{12}-\frac{3}{12}\right)\cdot\frac{1}{5}\)
\(=\frac{29}{12}\cdot\frac{1}{5}\)
\(=\frac{29}{60}\)
\(\frac{7}{15}\cdot\frac{15}{14}=\frac{1}{1}\cdot\frac{1}{2}=\frac{1}{2}\)
a) \(\left(2+\frac{2}{3}-\frac{1}{4}\right)\cdot\frac{1}{5}=\left(\frac{8}{3}-\frac{1}{4}\right)\cdot\frac{1}{5}=\frac{29}{12}\cdot\frac{1}{5}=\frac{29}{60}\)
b)\(\frac{7}{15}\cdot\frac{15}{14}=\frac{105}{210}=\frac{1}{2}\)
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a)\(x+\frac{15}{16}+\frac{7}{8}=\frac{15}{4}\)
\(x+\frac{29}{16}=\frac{15}{4}\)
\(x=\frac{15}{4}-\frac{29}{16}\)
\(x=\frac{31}{16}\)
b)\(x-\frac{27}{28}-\frac{9}{14}=\frac{13}{7}\)
\(x-\frac{45}{28}=\frac{13}{7}\)
\(x=\frac{13}{7}+\frac{45}{28}\)
\(x=\frac{97}{28}\)
c)\(x\times\frac{1}{5}+x+\frac{1}{6}=\frac{2}{3}\)
\(x\times\frac{1}{5}+x=\frac{2}{3}-\frac{1}{6}\)
\(x\times\left(\frac{1}{5}+1\right)=\frac{1}{2}\)
\(x\times\frac{6}{5}=\frac{1}{2}\)
\(x=\frac{1}{2}:\frac{6}{5}\)
\(x=\frac{5}{12}\)
d)\(x:14=\frac{1}{4}+\frac{2}{9}+\frac{3}{4}\)
\(x:14=\frac{11}{9}\)
\(x=\frac{11}{9}\times14\)
\(x=\frac{154}{9}\)
#H
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1,\frac{7}{5},\frac{15}{14},\frac{5}{7},\frac{1}{2},\frac{2}{5}\)
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(5/7-y)x14/5=6/5
5/7-y=6/5:14/5
5/7-y=3/7
y=5/7-3/7
x=2/7
Ta có : \(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)
\(\Rightarrow\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{12}{10}=\frac{6}{5}\)
\(\Rightarrow\left(\frac{5}{7}-y\right)=\frac{6}{5}:\frac{14}{5}\)
\(\Rightarrow\left(\frac{5}{7}-y\right)=\frac{30}{70}=\frac{3}{7}\)
\(y=\frac{5}{7}-\frac{3}{7}=\frac{2}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5/9 + 2/3 + 1/2 = 31/18
5/12 + 3/4 + 1/3 = 3/2
1/4 + 3/7 + 11/14 = 41/28
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{6}{9}+\frac{5}{7}+\frac{1}{3}\)\(=\frac{2}{3}+\frac{5}{7}+\frac{1}{3}\)\(=\left(\frac{2}{3}+\frac{1}{3}\right)+\frac{5}{7}\)\(=1+\frac{5}{7}=\frac{12}{7}\)
b) \(\frac{17}{7}+\frac{6}{5}-\frac{20}{14}\)\(=\frac{17}{7}+\frac{6}{5}-\frac{10}{7}\)\(=\left(\frac{17}{7}-\frac{10}{7}\right)+\frac{6}{5}\)\(=1+\frac{6}{5}\)\(=\frac{11}{5}\)
c) \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{72}\)\(=\frac{36}{72}+\frac{12}{72}+\frac{6}{72}+\frac{1}{72}=\frac{36+12+6+1}{72}=\frac{55}{72}\)
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