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Đề: Tìm x
\(12\times\left(x-6\right)=4\times x+12\)
\(12\times x-12\times6=4\times x+12\)
\(12\times x-72=4\times x+12\)
\(12\times x-4\times x=72+12\)
\(8\times x=84\)
\(x=84:8\)
\(x=10,5\)
\(12\times\left(x-6\right)=4\times x+12\)
\(12\times x-72=4\times x+12\)
\(12\times x-4\times x=12+72\)
\(8\times x=84\)
\(x=10,5\)
Ta có : (x + 3) + (x + 6) + (x + 9) + ...... + (x + 30) = 330
<=> (x + x + x + ...... + x) + ( 3 + 6 + 9 + ...... + 30 ) = 330
<=> 10x + 165 = 330
=> 10x = 2
=> x = 1/5
(x+x+x+..+x)+(3+6+9+...+30)
10x+165=330
10x=330-165
10x=165
x=165/10
x=16,5
\(1-x=\frac{29}{12}+\frac{32}{8}\)
\(\Rightarrow1-x=\frac{77}{12}\)
\(\Rightarrow x=1-\frac{77}{12}=\frac{-65}{12}\)
\(\frac{31}{8}.x-\frac{11}{4}=\frac{42}{12}.\frac{10}{8}-\frac{1}{3}\)
\(\Rightarrow\frac{31}{8}.x-\frac{11}{4}=\frac{35}{8}-\frac{1}{3}\)
\(\Rightarrow\frac{31}{8}.x-\frac{11}{4}=\frac{97}{24}\)
\(\Rightarrow\frac{31}{8}.x=\frac{97}{24}+\frac{11}{4}=\frac{163}{24}\)
\(\Rightarrow x=\frac{163}{24}:\frac{31}{8}=\frac{163}{93}\)
A= 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90
=1/(1.2)+1/(2.3)+1/(3.4)+1/(4.5)
+1/(5.6)+1/(6.7)+1/(7.8)
+1/(8.9)+1/(9.10)
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5.+1/5-1/6...
+1/9-1/10
=1-1/10
=9/10
thay x = a thôi đấy
chẳng động não gì cả
1.Tính :
\(\frac{12}{17}\):6=\(\frac{2}{17}\); 16:\(\frac{8}{11}\)=\(\frac{2}{11}\); 9:\(\frac{3}{5}\)x\(\frac{4}{15}\)=\(\frac{3}{5}\)x\(\frac{4}{15}\)=\(\frac{4}{25}\)
=12/17×1/6
=2/17
=16/1×11/8
=22
9/1×5/3×4/15
15/1×4/15
4/1
a) (x-12)*17:11=51
(x-12)=51:(17:11)
x-12=33
x=33+12
x=45
b) 4*(36-4*x)=64
(36-4*x)=64:4
(36-4*x)=16
x=16:(36-4)
x=0.5
c) (x+5)*19:13=57
(x+5)=57:(19:13)
x+5=39
x=39-5
x=34
b) 3.25.8+ 4.37.6+2.38.12
= 24.25+24.37+24.38
=24.(25+ 37+38)
=24.100
=2400
c) (563+745)-(463+545)
= (563-463)+(745+545)
= 100 + 100
= 200
12(x - 6) = 4x + 12
12x - 72 = 4x + 12
12x - 4x = 12 + 72
8x = 84
x = 84 : 8
x = 21/2
12 x (x - 6) = 4 x x + 12
12x - 72 = 4x + 12
12x - 4x = 72 + 12
8x = 84
x = 10,5
Vậy x = 10,5