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Bài 1:
a: -8/12<0<-3/-4
b: -56/24<0<7/3
c: 4/25<1<15/13
=>-4/25>-15/13
Bài 2:
a: =-60/45=-4/3
b: =4/15-3/2-8/5=8/30-45/30-48/30=-85/30=-17/6
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a) − 15 − 17 > 0 > 16 − 19 ⇒ − 15 − 17 > 16 − 19
b) 13 21 = 26 42 ; 9 14 = 27 42 . Do 26 42 < 27 42 ⇒ 13 21 < 9 14
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a: 3>2
=>5/3<5/2
b: 23/21>1
21/23<1
=>23/21>21/23
c: -15/-17>0
16/-19<0
=>-15/-17>16/-19
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a ) − 1 > − 2 ; b ) − 9 11 < − 8 11 ; c ) 1 6 > − 7 10 ; d ) 29 20 < 2
\(\dfrac{12}{-15}=\dfrac{12:-3}{-15:-3}=\dfrac{-4}{5}\)
Ta có:
Mẫu số chung 2 phân số: 95
\(\dfrac{-4}{5}=\dfrac{-4\cdot19}{5\cdot19}=\dfrac{-76}{95}\)
\(\dfrac{-15}{19}=\dfrac{-15\cdot5}{19\cdot5}=\dfrac{-75}{95}\)
Vì \(-76< -75\) nên\(\dfrac{-76}{95}< \dfrac{-75}{95}\)
Vậy \(\dfrac{12}{-15}< \dfrac{-15}{19}\)
Rút gọn:
\(\dfrac{12}{-15}=\dfrac{12:3}{-15:3}=\dfrac{4}{-5}\)
Ta có:
\(\dfrac{4}{-5}\) và \(\dfrac{15}{-19}\) (Đổi \(\dfrac{-15}{19}=\dfrac{15}{-19}\))
Quy đồng 2 phân số:
Mẫu số chung: \(95\).
Ta có:
\(\dfrac{4}{-5}=\dfrac{4\cdot\left(-19\right)}{-5\cdot\left(-19\right)}=\dfrac{-76}{95};\dfrac{15}{-19}=\dfrac{15\cdot\left(-5\right)}{-19\cdot\left(-5\right)}=\dfrac{-75}{95}\)
Mà \(\dfrac{76}{95}>\dfrac{75}{95}\Rightarrow\dfrac{-76}{95}< \dfrac{-75}{95}\)
Vậy \(\dfrac{12}{-15}< \dfrac{-15}{19}\)