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118,24 - ( X : 5 + X x 3 ) = 27.12 x 2
=> X : 5 + X x 3 = 118,24 - 54,24
=> X x 1/5 + X x 3 = 64
=> X x ( 1 / 5 + 3 ) = 64
=> X x 16/5 = 64
=> X = 20
vậy X = 20
118,24 - ( X : 5 + X x 3 ) = 27,12 x 2
118,24 - ( x : 5 + X x 3 ) = 54,24
X : 5 + X x 3 = 118,24 - 54,24
X : 5 + X x 3 = 64
X x 1/5 + X x 3 = 64
X x ( 1/5 + 3 ) = 64
X x 3,2 = 64
X = 64 : 3,2
X = 20
~Hok tốt~
K nhoa ~~
118,24 - (x:5+x.3)= 54,24
x:5 + x.3 = 118,24 - 54,24 = 64
1/5 x + 15/5 x = 64
16/5 x = 64
x = 64 : 16/5 = 20
118,24 - ( x : 5 - x x 3 ) = 27,12 x 2
118,24 - ( x : 5 - x x 3 ) = 54,24
x : 5 - x x 3 = 118,24 - 54,24
x : 5 - x x 3 = 64
1/5x + 15/5x = 64
16/5x = 64
x = 64 : 16/5 = 20 = > x = 20
118,24 - ( \(x\)x \(\frac{1}{5}\)+ \(x\)x 3 ) = 54,24
\(x\)x ( \(\frac{1}{5}\)+ 3 ) = 118,24 - 54,24
\(x\)x \(\frac{16}{5}\) = 64
\(x\) = 64 : \(\frac{16}{5}\)
\(x\) = 20
\(118,24-\left(x:5+x.3\right)=27,12.2\)
\(\Leftrightarrow118,24-\left(x:5+x.3\right)=54,24\)
\(\Leftrightarrow x:5+x.3=118,24-54,24\)
\(\Leftrightarrow x.\frac{1}{5}+x.3=64\)
\(\Leftrightarrow x.\left(\frac{1}{5}+3\right)=64\)
\(\Leftrightarrow x.\frac{16}{5}=64\)
\(\Leftrightarrow x=64:\frac{16}{5}\)
\(\Leftrightarrow x=20\)
\(\left(6:3,5-1\dfrac{1}{6}\times\dfrac{6}{7}\right):\left(4,2\times\dfrac{10}{11}+5\dfrac{2}{11}\right)\\ =\left(\dfrac{12}{7}-\dfrac{7}{6}\times\dfrac{6}{7}\right):\left(\dfrac{21}{5}\times\dfrac{10}{11}+\dfrac{57}{11}\right)\\ =\left(\dfrac{17}{7}-1\right):\left(\dfrac{42}{11}+\dfrac{57}{11}\right)\\ =\dfrac{10}{7}:9\\ =\dfrac{10}{63}\)
\(\left(6:\dfrac{3}{5}-1\dfrac{1}{6}\times\dfrac{6}{7}\right):\left(4,2\times\dfrac{10}{11}+5\dfrac{2}{11}\right)\)
\(=\left(6\times\dfrac{5}{3}-\dfrac{7}{6}\times\dfrac{6}{7}\right):\left(\dfrac{21}{5}\times\dfrac{10}{11}+\dfrac{57}{11}\right)\)
\(=\left(10-1\right):\left(\dfrac{42}{11}+\dfrac{57}{11}\right)=9:9=1\)
Lời giải:
$118,24-(2:5+x\times 3)=27,12\times 2$
$118,24-(0,4+x\times 3)=54,24$
$0,4+x\times 3=118,24-54,24=64$
$x\times 3=64-0,4=63,6$
$x=63,6:3=21,2$