Câu hỏi của nguyễn thị minh thư

Question

{1/1.300+1/2.301+1/3.302+...+1/101.400}:{1/1.102+1/2.103+1/3.104+...=1/299.400}

Đỗ Hoàng Minh · Accepted Answer

A=11.300+12.301+13.302+...+1101.400�=11.300+12.301+13.302+...+1101.400A=1299.(11−1300+12−1301+13−13012+...+1101−1400)�=1299.(11−1300+12−1301+13−13012+...+1101−1400)A=1299.(11−1400)�=1299.(11−1400)A=1299.399400�=1299.399400A=399119600�=399119600B=11.102+12.103+13.104+...+1299.400�=11.102+12.103+13.104+...+1299.400B=1101.(11−1102+12−1103+....+1299−1400)�=1101.(11−1102+12−1103+....+1299−1400)B=1101.(11−1400)�=1101.(11−1400)B=1101.399400�=1101.399400B=39940400�=39940400⇒AB=39911960039940400=101299Câu trả lời: A=11.300+12.301+13.302+...+1101.400�=11.300+12.301+13.302+...+1101.400A=1299.(11−1300+12−1301+13−13012+...+1101−1400)�=1299.(11−1300+12−1301+13−13012+...+1101−1400)A=1299.(11−1400)�=1299.(11−1400)A=1299.399400�=1299.399400A=399119600�=399119600B=11.102+12.103+13.104+...+1299.400�=11.102+12.103+13.104+...+1299.400B=1101.(11−1102+12−1103+....+1299−1400)�=1101.(11−1102+12−1103+....+1299−1400)B=1101.(11−1400)�=1101.(11−1400)B=1101.399400�=1101.399400B=39940400�=39940400⇒AB=39911960039940400=101299

Chúng tôi đề xuất

Tài nguyên

Ứng dụng mobile

Bảng xếp hạng

Các khóa học có thể bạn quan tâm

Yêu cầu VIP