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a: \(=3\cdot\dfrac{6+14-9}{42}\cdot\dfrac{14}{11}\)
\(=3\cdot\dfrac{11}{42}\cdot\dfrac{14}{11}=1\)
b: \(=\dfrac{19}{5}\cdot\dfrac{11}{10}+\dfrac{9}{5}\cdot\dfrac{7}{3}\)
\(=\dfrac{209}{50}+\dfrac{63}{15}=4.18+4.2=8,38\)

\(\frac{11}{4}-\frac{3}{x}=\frac{5}{14}\)
\(\Leftrightarrow\frac{3}{x}=\frac{11}{4}-\frac{5}{14}\)
\(\Leftrightarrow\frac{3}{x}=\frac{67}{28}\)
\(\Leftrightarrow x.67=3.28\)
\(\Leftrightarrow x.67=84\)
\(\Leftrightarrow x=\frac{84}{67}\)
11/4 - 3/x = 5/14
3/x = 11/4 - 5/14
3/x = 67/28
=> 67 * x = 28 * 3
67 * x = 84
x = 84/67
Vậy.......




Ta có : \(\frac{2}{2.5}+\frac{2}{5.8}+\frac{2}{8.11}+\frac{2}{11.14}+\frac{2}{14.17}\)
\(=\frac{2}{3}\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}\right)\)
\(=\frac{2}{3}\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+.....+\frac{1}{14}-\frac{1}{17}\right)\)
\(=\frac{2}{3}\left(\frac{1}{2}-\frac{1}{17}\right)=\frac{2}{3}.\frac{15}{34}=\frac{5}{17}< 1\)
nó = 2/3(3/2x5+3/5x8+...+3/14x17)
=2/3(1/2-1/5+1/5-1/8+...+1/14-1/17)
=2/3x(1/2-1/17)
=2/3x15/34=5/17<1( điều phải chứng minh)


a) 8/15 + 1 = 23/15
b) 3/14 + 11/14 - 2/3 = 1- 2/3 = 1/3
c) 7/15 * (5/3+2/3) = 7/15 * 7/3= 49/45
d) 6/11 + 5/11 - 3/5 = 1 - 3/5 = 2/5

a.\(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)
\(\frac{3}{x-1}=\frac{11}{14}-\frac{5}{14}\)
\(\frac{3}{x-1}=\frac{3}{7}\)
\(\Rightarrow x-1=7\)
\(x=7+1\)
Vậy \(x=8\)
b.\(\frac{42}{25}:\frac{2x+1}{5}=\frac{6}{5}\)
\(\frac{2x+1}{5}=\frac{42}{25}:\frac{6}{5}\)
\(\frac{2x+1}{5}=\frac{7}{5}\)
\(\Rightarrow2x+1=7\)
\(2x=7-1\)
\(2x=6\)
\(x=6:2\)
\(x=3\)
a.\(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)
\(\frac{3}{x-1}=\frac{11}{14}-\frac{5}{14}=\frac{3}{7}\)
\(\Rightarrow x-1=7\)
\(x=7+1=8\)
VẬY, \(x=8\)
b. \(\frac{42}{25}:\frac{2x+1}{5}=\frac{6}{5}\)
\(\frac{2x+1}{5}=\frac{42}{25}:\frac{6}{5}=\frac{7}{5}\)
\(\Rightarrow2x+1=7\)
\(2x=7-1=6\)
\(x=6:2=3\)
VẬY, \(x=3\)

\(\frac{5+8+11+14+...+68+71}{2\times43+3\times43+43\times5+7}\).
Xét tử số: 5+ 8+ 11+ 14+...+ 68.
Có số các số hạng là:
( 68- 5): 3+ 1= 22
Tử số là:
( 68+ 5)x 22: 2= 803
Xét mẫu số: 2x 43+ 3x 43+ 43x 5+ 7=( 2+ 3+ 5)x 43+ 7= 10x 43+ 7= 430+ 7= 437.
=> \(\frac{5+8+11+14+...+68+71}{2\times43+3\times43+43\times5+7}\)= \(\frac{803}{437}\).
11/14-3/x=5/14
3/x = 11/14 - 5/14
3/x = 3/7
=> x = 7
Vậy x = 7