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Với mọi giá trị của \(x\in R\) ta có:
\(\left|x+1\right|\ge0;\left|x+1,2\right|\ge0;\left|x+1,3\right|\ge0;\left|x+1,4\right|\ge0\)
\(\Rightarrow\left|x+1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|\ge0\)
mà \(\left|x+1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|=5x\)
nên \(5x\ge0\Rightarrow x\ge0\)
\(\Rightarrow\left\{{}\begin{matrix}\left|x+1\right|=x+1\\\left|x+1,2\right|=x+1,2\\\left|x+1,3\right|=x+1,3\\\left|x+1,4\right|=x+1,4\end{matrix}\right.\)
\(\Rightarrow x+1+x+1,2+x+1,3+x+1,4=5x\)
\(\Rightarrow4x+4,9=5x\Rightarrow x=4,9\)
Chúc bạn học tốt!!!
\(\left|x+1\right|\ge0\) \(\left|x+1,2\right|\ge0\)
\(\left|x+1,3\right|\ge0\) \(\left|x+1,4\right|\ge0\)
\(\Leftrightarrow\left|x+1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|\ge0\)
\(\Leftrightarrow x+1+x+1,2+x=1,3+x+1,4=5x\)
\(4x+4,9=5x\)
\(\Leftrightarrow x=4,9\)
= 34,8: ( 1,8+ 4) - 1,9
=34,8: 2, 2- 1,9
= 348/ 10x 10/ 22- 19/10
=174/ 5x 5/ 11- 19/10
= 174/11- 19/11
= 174- 19/11
=155/11
a) \(\left|3,5-x\right|=1,3\)
\(\Rightarrow\left[{}\begin{matrix}3,5-x=1,3\\3,5-x=-1,3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3,5-1,3\\x=3,5+1,3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2,2\\x=4,8\end{matrix}\right.\)
b) \(1,6-\left|x-0,2\right|=0,4\)
\(\Rightarrow\left|x-0,2\right|=1,2\)
\(\Rightarrow\left[{}\begin{matrix}x-0,2=1,2\\x-0,2=-1,2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=1,2+0,2\\x=-1,2+0,2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=1,4\\x=-1\end{matrix}\right.\)
\(\left|3,5-x\right|=1,3\)
\(\Rightarrow\left[{}\begin{matrix}3,5-x=1,3\Rightarrow x=2,2\\3,5-x=-1,3\Rightarrow x=4,8\end{matrix}\right.\)
\(1,6-\left|x-0,2\right|=0,4\)
\(\Rightarrow\left|x-0,2\right|=1,2\)
\(\Rightarrow\left[{}\begin{matrix}x-0,2=1,2\Rightarrow x=1,4\\x-0,2=-1,2\Rightarrow x=-1\end{matrix}\right.\)
\(\left|x-1,5\right|+\left|2,5-x\right|=0\)
\(\left\{{}\begin{matrix}\left|x-1,5\right|\ge0\\\left|2,5-x\right|\ge0\end{matrix}\right.\)
\(\Rightarrow\left|x-1,5\right|+\left|2,5-x\right|\ge0\)
Dấu "=" xảy ra khi:
\(\left\{{}\begin{matrix}\left|x-1,5\right|=0\Rightarrow x=1,5\\\left|2,5-x\right|=0\Rightarrow x=2,5\end{matrix}\right.\)
\(1,5\ne2,5\Rightarrow x\in\varnothing\)
2x3,12x1,25x0,25x10=2x3,12x(1,25:0,25x10)
=2x3,12 x50
=100x3,12=312
a, \(\left(x-158\right):6=20\)
\(x-158=20.6\)
\(x-158=120\)
\(x=120+158\)
\(x=278\)
~~~Hok tốt~~~
a) \(\left(x-158\right):6=20\)
\(\Leftrightarrow x-158=\frac{20}{6}=\frac{10}{3}\)
\(\Leftrightarrow x=\frac{10}{3}+158\)
\(\Leftrightarrow x=\frac{484}{3}\)
Vậy : \(x=\frac{484}{3}\)
b) \(x-1,25.4=2,5\)
\(\Leftrightarrow x-5=2,5\)
\(\Leftrightarrow x=2,5+5\)
\(\Leftrightarrow x=7,5\)
Vậy : \(x=7,5\)
c) \(x+0,25=\frac{43}{4}-\frac{18}{5}\)
\(\Leftrightarrow x+\frac{1}{4}=\frac{143}{20}\)
\(\Leftrightarrow x=\frac{143}{20}-\frac{1}{4}\)
\(\Leftrightarrow x=\frac{69}{10}\)
Vậy : \(x=\frac{69}{10}\)
`5,17 : ( -1,3) + 1,43. 1,1 + 39. 0,143 + 7,83 : (-1,3)`
`=5,17 .(-10)/(13) + 7,83 .(-10)/13 +0,143.11 + 39. 0,143 `
`= (-10)/13 .( 5,17+7,83) + 0,143.(11+39)`
`= -10 + 7,15`
`=-2,85`
5,17:(−1,3)+1,43.1,1+39.0,143+7,83:(−1,3)=(5,17+7,83):(−1,3)+1,43.1,1+1,43.3,9=(5,17+7,83):(−1,3)+1,43(1,1+3,9)=13:(−1,3)+1,43.5=−10+7,15=−2,85
a.
\(1,25\times4-x=2,5\)
\(5-x=2,5\)
\(x=5-2,5\)
\(x=2,5\)
b.
\(\left(158-x\right)\div7=20\)
\(158-x=20\times7\)
\(158-x=140\)
\(x=158-140\)
\(x=18\)
c.
\(x-0,25=\frac{43}{4}-\frac{18}{5}\)
\(x-\frac{1}{4}=\frac{43}{4}-\frac{18}{5}\)
\(x=\frac{43}{4}-\frac{18}{5}+\frac{1}{4}\)
\(x=\left(\frac{43}{4}+\frac{1}{4}\right)-\frac{18}{5}\)
\(x=\frac{44}{4}-\frac{18}{5}\)
\(x=11-\frac{18}{5}\)
\(x=\frac{37}{5}\)
a. 1,25 × 4 - x = 2,5
5- x= 2,5
x= 5-2,5
x=2,5
b.(158- x) :7= 20
158- x= 20x7
158 -x= 140
x=158- 140
x=18
c. x- 0,25= \(\frac{43}{4}+\frac{18}{5}\)
x- 0,25=14,35
x= 14,35+ 0,25
x=14,6
a, 0,25 - x = -0,75
x = 0,25 - -0,75
x = 1
b,x:(-3)= -\(\frac{2}{3}\)
x = -\(\frac{2}{3}\) >< -3
x = -2
c,(1,1.x-9).\(\frac{2}{5}\)=80%
1,1 >< x -9 = \(\frac{80}{100}\) : \(\frac{2}{5}\)
1,1 >< x -9 = 2
1,1 >< x = 2 + 9
1,1 >< x = 11
x =11 : 1,1
x = 10
d,2.x-30%.x=-1,7
x >< (2-0,3)=1,7
x >< 0,7 = 1,7
x = 1,7 : 0,7
x = 2.42857142857
5.76576