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B = 1 + 4 + 42 +...+ 4200 + 4201
=> 4B = 4 + 42 +43 +...+ 4201 + 4202
=> 4B-B = 4202 - 1
3B = 4202 -1
\(\Rightarrow B=\frac{4^{202}-1}{3}\)
4B = 4 + 4^2 + 4^3 + ... + 4^202
4B - B = ( 4 + 4^2 + 4^3 + ... + 4^202 ) - ( 1 + 4 + 4^2 + ... + 4^201 )
3B = 4^202 - 1
B = \(\frac{4^{202}-1}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2x-5+x=2^0\)
\(2x+x-5=2^0\)
\(3x-5=2^0=1\)
\(3x=1+5=6\)
\(x=6:3\)
\(x=2\)
Vậy \(x=3\)
2x - 5 + x = 2^0
2x - 5 + x = 1
2x + x - 5 = 1
3x - 5 =1
3x = 6
x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
a){720:[41-(7.2\(^2\)- X)] }:(2\(^3\).5)=1
{720:[41-(7.4-X)] }:(8.5)=1
{720:[41-(28-X)] }:40=1
41-(28-X):40=1.720
41-(28-X):40=720
(28-X):40=720+41
(28-X):40=716
28-X =716.40
28-X=28640
X=28-28640
X=(-28612)
b)420+65.4=(x+175):5+30
420+260=(x+175):5+30
280=(x+175):5+30
(x+175):5=280-30
(x+175):5=250
x+175=250.5
x+175=1250
x=1250-175
x=1075
c)(32.15):2=(x+70):14-40
480:2=(x+70):14-40
240=(x+70):14-40
(x+70):14=240+40
(x+70):14=280
x+70=280.14
x+70=3920
x=3920-70
x=3850
1024 : ( 14 . 25 + 15 . 25)
1024 : [ 25 . ( 14 + 15 ) ]
1024 : [ 25 . 29 ]
1024 : [ 32 . 29 ]
1024 : 928
32/29
1024: (14x \(2^5\)+15x \(^{2^5}\)) = 1024: (14+15x \(^{2^5}\))
=1024: (29 x 32)
=1024:928
=\(\frac{32}{29}\)