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b/1.2.3.....2013 - 1.2.3....2012-1.2.3...20122
= (1.2.3...2012.2013-1.2.3...2012)-1.2.3...2012.2012
= 1.2.3...2012(2013-1-2012)
=1.2.3...2012.0=0
\(\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}=\frac{9.2}{9}=2\)
\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{6^9.2^{10}+6^{10}.2^{10}}=\frac{2^{19}.3^9+3^9.5.2^{18}}{6^9.2^{10}.\left(1+6\right)}=\frac{2^{18}.3^9.\left(2+5\right)}{2^9.3^9.2^{10}.7}=\frac{2^{18}.7}{2^{19}.7}=\frac{1}{2}\)
a) 42 . 57 + 43 . 42 - 600
= 2394 + 1806 - 600
= 4200 - 600
= 3600.
b) 22 . 52 - 64 : 23
= 4 . 25 - 64 : 8
= 100 - 8
= 92
c) 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - 33 ]
= 120 - [ 100 - 27 ]
= 120 - 73
= 47.
1.Thực hiện các phép tính sau
a)42.57+43.42-600
b)22.52-64: 23
c) 120-[100-(5-2)3]
d)(102+112+122):(132+142)
a) 42 . 57 + 43 . 42 - 600
= 2394 + 1806 - 600
= 4200 - 600
= 3600.
b) 22 . 52 - 64 : 23
= 4 . 25 - 64 : 8
= 100 - 8
= 92
c) 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - 33 ]
= 120 - [ 100 - 27 ]
= 120 - 73
= 47.
(214+215+216):(211+212+213)=214(1+2+22):211(1+2+22)=214:211=214-11=23=8
\(\left(2^{14}+2^{15}+2^{16}\right):\left(2^{11}+2^{12}+2^{13}\right)=\left(2^{14}:2^{11}\right)+\left(2^{15}:2^{12}\right)+\left(2^{16}:2^{13}\right)=8+8+8=24\)
a,113-3+20
=1328+20
=1348
b,300+7781+1425
=9506
c,7+36-40
=43-40=3
a,
115 : 112 - 33 : ( 11 + 23 ) + 22 x 30 x 5
= 11( 5 - 2 ) - 27 : ( 1 + 8 ) + 4 x 1 x 5
= 113 - 27 : 9 + 4 x 5
= 1331 - 3 + 20
= 1328 + 20
= 1348
b,
12 x 25 + 31 x 251 + 57x 25
= 12 x 25 + 57 x 25 + 31 x 251
= ( 12 + 57 ) x 25 + 31 x 251
= 69 x 25 + 31 x 251
= 1725 + 7781
= 9506
c,
15 - 23 + 4 x 32 - 5 x 8
= 15 - 8 + 4 x 9 - 40
= 15 - 8 + 36 - 40
= 7 + 36 - 40
= 43 - 40
= 3
1 ) 365
2)0
=100+121+144=365
1.2.3.4.5.6.7.8.9-1.2.3.4.5.6.7.8-1.2.3.4.5.6.7.8.8=362880-3265920-2903040=-5806080
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