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Tình GT của bt (Tính nhanh nếu có thể)
1) 13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1
=13-(12+9-10-11)+(8+5-7-6)+(3+2-4-1)
=13+0+0+0=13
2) 49 - (-54) - 23
=49+54-23
=80
3) 100 + (-520) + 1140 + (-620)
=( 100+1140)+(-620)+-520)
= 100
a) 13 - 18 - (-42) - 15
=13-18+42-15
=22
TICK CHO
T
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Bài 1:
\(\frac{3}{5}+\frac{4}{15}=\frac{9}{15}+\frac{4}{15}=\frac{13}{15}\)
\(\frac{5}{6}:\frac{-7}{12}=\frac{5}{6}.\frac{-12}{7}=\frac{-60}{42}=\frac{-10}{7}\)
\(\frac{-21}{24}:\frac{-14}{8}=\frac{-21}{24}.\frac{-8}{14}=\frac{168}{336}=\frac{1}{2}\)
\(\frac{4}{5}:\frac{-8}{15}=\frac{4}{5}.\frac{-15}{8}=\frac{-60}{40}=\frac{-3}{2}\)
\(\frac{5}{12}-\frac{-7}{6}=\frac{5}{12}+\frac{7}{6}=\frac{5}{12}+\frac{14}{12}=\frac{19}{12}\)
\(\frac{-15}{16}.\frac{8}{25}=\frac{-120}{400}=\frac{-3}{10}\)
Bài 2 :
\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)\)
\(=\frac{34}{5}-\left(\frac{5}{3}+\frac{19}{5}\right)\)
\(=\frac{34}{5}-\frac{5}{3}-\frac{19}{5}\)
\(=\left(\frac{34}{5}-\frac{19}{5}\right)-\frac{5}{3}\)
\(=3-\frac{5}{3}\)
\(=\frac{4}{3}\)
\(6\frac{5}{7}-\left(1\frac{2}{3}+2\frac{5}{7}\right)\)
\(=\frac{47}{7}-\left(\frac{5}{3}+\frac{19}{7}\right)\)
\(=\frac{47}{7}-\frac{5}{3}-\frac{19}{7}\)
\(=\left(\frac{47}{7}-\frac{19}{7}\right)-\frac{5}{3}\)
\(=4-\frac{5}{3}\)
\(=\frac{7}{3}\)
\(\frac{4}{19}.\frac{-3}{7}+\frac{-3}{7}.\frac{15}{19}+\frac{5}{7}\)
\(=\left(\frac{4}{19}+\frac{15}{19}\right).\frac{-3}{7}+\frac{5}{7}\)
\(=1.\frac{-3}{7}+\frac{5}{7}\)
\(=\frac{-3}{7}+\frac{5}{7}\)
\(=\frac{2}{7}\)
\(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.1\)
\(=\frac{5}{9}\)
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Mik đọc công thức bạn tự làm nhé áp dụng công thức nhé:
b1: a)SCSH: ( 2017 - 13 ) : 3 + 1 = 669 ( số hạng )
b2: Tổng: ( 2017 + 13 ) . 669 : 2 = 679035
b) SCSH: ( 2000 - 2 ) : 2 + 1 = 1000 ( số hạng )
Tổng: ( 2000 + 2 ) . 1000 : 2 = 1001000
c)SCSH: ( 102 - 1 ) : 1 + 1 = 102 ( số hạng )
Tổng: ( 102 + 1 ) . 102 : 2 = 5253
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\(\frac{3}{5}-\frac{1}{9}-\frac{1}{2}-\frac{1}{127}+\frac{7}{18}+\frac{4}{35}+\frac{2}{7}\)=\((\frac{1}{9}-\frac{1}{2}+\frac{7}{18})+(\frac{3}{5}+\frac{2}{7}+\frac{4}{35})+\frac{1}{127}\)=\(0+1+\frac{1}{127}\)=\(1+\frac{1}{127}=\frac{128}{127}\)
lần đầu VY viết sai đề
đáng lẻ số cuối là 127 hay 129 ko thể là số chắn [ ( 128 + 1 ) x ( 128 - 1 ) : 2 + 1 ) : 2 = ( sai đề )