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\(\dfrac{3}{4}.\dfrac{2}{3}-\dfrac{1}{6}.\dfrac{3}{4}-\dfrac{3}{4}.\dfrac{1}{2}\)
= \(\dfrac{3}{4}.\left(\dfrac{2}{3}-\dfrac{1}{6}-\dfrac{1}{2}\right)\)
= \(\dfrac{3}{4}.0\)
= 0
\(\dfrac{3}{4}\cdot\dfrac{2}{3}-\dfrac{1}{6}\cdot\dfrac{3}{4}-\dfrac{3}{4}\cdot\dfrac{1}{2}\)
\(=\dfrac{3}{4}\left(\dfrac{2}{3}-\dfrac{1}{6}-\dfrac{1}{2}\right)\)
\(=\dfrac{3}{4}\cdot\left(\dfrac{4}{6}-\dfrac{1}{6}-\dfrac{3}{6}\right)\)
=0
\(1-\dfrac{2}{7}-\dfrac{1}{4}=\dfrac{7}{7}-\dfrac{2}{7}=\dfrac{1}{4}=\dfrac{5}{7}-\dfrac{1}{4}=\dfrac{20}{28}-\dfrac{7}{28}=\dfrac{13}{28}\)
\(x:\dfrac{3}{4}=1-\dfrac{2}{5}\\ \Rightarrow x\cdot\dfrac{4}{3}=\dfrac{3}{5}\\ \Rightarrow x=\dfrac{3}{5}:\dfrac{4}{3}=\dfrac{9}{20}\)
\(x:\dfrac{3}{4}=1-\dfrac{2}{5}\)
\(\Rightarrow x:\dfrac{3}{4}=\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{3}{5}\times\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{9}{20}\)
13/120+11/24-17/30
13/120+55/120-68/120
68/120-68/120
0
18/100+9/45-2/25
\(\frac{1}{2}-\frac{1}{3}=\frac{1x3}{2x3}-\frac{1x2}{3x2}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}\)
\(1-\frac{2}{3}=\frac{1}{1}-\frac{2}{3}=\frac{1x3}{1x3}-\frac{2}{3}=\frac{3}{3}-\frac{2}{3}=\frac{1}{3}\)
\(2-\frac{3}{4}-\frac{1}{4}=\frac{5}{4}-\frac{1}{4}=\frac{4}{4}=1\)
\(\frac{7}{6}-\frac{2}{3}=\frac{7}{6}-\frac{2x2}{3x2}=\frac{7}{6}-\frac{4}{6}=\frac{3}{6}=\frac{1}{2}\)
\(\frac{7}{6}-\frac{1}{2}=\frac{7}{6}-\frac{1x3}{2x3}=\frac{7}{6}-\frac{3}{6}=\frac{4}{6}=\frac{2}{3}\)