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\(2x^3y-2xy^3-4xy^2-2xy\)
\(=2xy.\left(x^2-y^2-2y-1\right)\)
\(=2xy.[x^2-\left(y^2+2y+1\right)]\)
\(=2xy.[x^2-\left(y+1\right)^2]\)
\(=2xy.\left(x+y+1\right).\left(x-y-1\right)\)
Vậy chọn đáp án A
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\(a,=\left(x+y\right)^2-5^2=\left(x+y+5\right)\left(x+y-5\right)\)
\(b,=\left(a-1\right)^2-1-\left(2b+1\right)^2-1=\)
\(c,=\left(a-b\right)\left(a+b\right)-5\left(a+b\right)=\left(a+b\right)\left(a-b-5\right)\)
a,( x2 + 2xy + y2 ) -25
=( x + y )2 - 52
=( x + y + 5) ( x + y - 5)
b,
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a.2x2y-6xy2
=2xy(x-3y)
b.3x(x-1)+7x2(x-1)
=(x-1)(3x+7x2)
c.3x(x-a)+5a(a-x)
=3x(x-a)-5a(x-a)
=(x-a)(3x-5a)
d.x2+6xy+y2
=(x-y)2
e.125x3+y6
=(5x)3+(y2)3
=(5x+y2)(10x2-5xy+y4)
f.5x2y-10xyz+5xz2
=5x(y2-2yz+z2)
=5x(y-z)2
g.x2-2xy+y2-x2+yz
=(x-y)2-x2+yz
=(x-y-x)(x-y+x)+yz
h.x2-x-6
=(x2)-2x-3x-6
=x(x-2)-3(x-2)
=(x-2)(x-3)
i.x4+4x2+5
=(x2)2+4x2+5
=(x2)2+4x2+2-2+5
=(x2+2)2-3
nhung bai nay de lam bn cu thay thua so chung la nhom thui, bn xem mk lam rui lam tip nhe
a) = 2xy(x - 3y)
b) = (x-1)(3x+7x2) = x(3+7x)(x-1)
c) = (x-a)(3x-5a) bn đổi + 5a(a-x) = -5a(x-a)
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a) x2 + xy + y - 1 = (x2 - 1) + (xy + y) = (x - 1)(x + 1) + y(x + 1) = (x + 1)(x + y - 1)
b) 4 - x2 + 2xy - y2 = 4 - (x2 - 2xy + y2) = 4 - (x - y)2 = (x - y + 2)(4 - x + y)
c) 8x2 - 18y2 = 2(4x2 - 9y2) = 2[(2x)2 - (3y)2] = 2(2x - 3y)(2x + 3y)
d) 8x3 - 4x2 - 6xy - 9y2 - 27y3
= (8x3 - 27y3) - (4x2 + 6xy + 9y2)
= (2x - 3y)(4x2 + 6xy + 9y2) - (4x2 + 6xy + 9y2)
= (2x - 3y - 1)(4x2 + 6xy + 9y2)
e) 4x2 - x - 3 = 4x2 - 4x + 3x - 3 = 4x(x - 1) + 3(x - 1) = (x - 1)(4x + 3)
f) 4x2 - 8x + 3 = 4x2 - 2x - 6x + 3 = 2x(2x - 1) - 3(2x - 1) = (2x - 3)(2x - 1)
\(a^2-b^2-5a+5b=\left(a+b\right)\left(a-b\right)-5\left(a-b\right)=\left(a+b-5\right)\left(a-b\right)\)
\(x^2-6xy+9y^2-25=\left(x-3y\right)^2-5^2=\left(x-3y+5\right)\left(x-3y-5\right)\)
\(49-x^2-y^2+2xy=7^2-\left(x-y\right)^2=\left(7-x+y\right)\left(7+x-y\right)\)
THX BẠN