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= -2 + 30 -3 + 4-6457

= 28 - 3 + 4 -6457

= 29 - 6457

= -6448

1-3+30-3+4-6475

=28-3+4-6457

=25+4-6457

=29-6475

= -6446

16 tháng 11 2020

B=1+1/2*(1+2)*2/2+1/3*(1+3)*3/2+....+1/30*(1+30)*30/2

=1+1+2/2+1+3/2+...+1+30/2

=2+3+4+...+31/2

=(31+2)*30/2 phần 2

=) B=247,5

27 tháng 12 2017

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28 tháng 12 2017

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16 tháng 10 2021

\(1,\\ a,\Leftrightarrow x-\dfrac{1}{3}=0\Leftrightarrow x=\dfrac{1}{3}\\ b,\Leftrightarrow\left[{}\begin{matrix}x-4=4\\x-4=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=0\end{matrix}\right.\\ c,\Leftrightarrow2x+1=-2\Leftrightarrow x=-\dfrac{3}{2}\\ 2,\\ a,=1\\ b,=\left(\dfrac{13}{4}\right)^2=\dfrac{169}{16}\\ c,=\left(-\dfrac{7}{4}\right)^2=\dfrac{49}{16}\\ d,=\left(\dfrac{3}{7}\right)^{20}:\left(\dfrac{3}{7}\right)^{12}=\left(\dfrac{3}{7}\right)^8=...\\ e,=\left(3\cdot5\cdot\dfrac{2}{3}\right)^2=10^2=100\)

28 tháng 6 2019

c) Đặt \(A=2^0+2^1+2^2+...+2^{50}\)

\(\Leftrightarrow2A=2^1+2^2+2^3...+2^{51}\)

\(\Leftrightarrow2A-A=2^1+2^2+2^3...+2^{51}\)\(-2^0-2^1-2^2-...-2^{50}\)

\(\Leftrightarrow A=2^{51}-2^0=2^{51}-1< 2^{51}\)

Vậy \(2^0+2^1+2^2+...+2^{50}< 2^{51}\)

28 tháng 6 2019

a)Ta có: \(\hept{\begin{cases}2^{30}=\left(2^3\right)^{10}=8^{10}\\3^{30}=\left(3^3\right)^{10}=27^{10}\\4^{30}=\left(2^2\right)^{30}=2^{60}\end{cases}}\)và \(\hept{\begin{cases}3^{20}=\left(3^2\right)^{10}=9^{10}\\6^{20}=\left(6^2\right)^{10}=36^{10}\\8^{20}=\left(2^3\right)^{20}=2^{60}\end{cases}}\)

Mà \(8^{10}< 9^{10}\)\(27^{10}< 36^{10}\);\(2^{60}=2^{60}\)nên

\(8^{10}+27^{10}+2^{60}< 9^{10}+36^{10}+2^{60}\)

hay \(2^{30}+3^{30}+4^{30}< 3^{20}+6^{20}+8^{20}\)

8 tháng 8 2017

\(VT=1+2+2^3+...+2^{100}\)

\(2VT=2\left(1+2+2^3+...+2^{100}\right)\)

\(2VT=2+2^2+2^3+...+2^{101}\)

\(2VT-VT=\left(2+2^2+2^3+...+2^{101}\right)-\left(1+2+2^2+2^3+...+2^{100}\right)\)\(VT=2^{101}-1\)

\(VT=VP\)

8 tháng 8 2017

Thằng phúc chết tiệt, làm giúp ng` ta ko làm hết đuy, còn làm dở =))

Bài 2 :

a) Ta có :

\(3^{30}< 3^{34}\)

\(3^{30}=\left(3^3\right)^{10}=27^{10}\)

\(5^{20}=\left(5^2\right)^{10}=25^{10}\)

\(27^{10}>25^{10}\Leftrightarrow3^{30}>5^{20}\) (Mà \(3^{30}< 3^{34}\))

\(\Leftrightarrow5^{20}< 3^{34}\)