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1+2+3+4+5+........+2018=?
số các số hạng là
( 2018 - 1 ) : 1 + 1 = 2018
tổng là
( 2018 + 1 ) x 2018 : 2 = 2037171
đáp số 2037171
hok tốt
\(x-\frac{3}{5}=\frac{4}{7}\) \(x+\frac{3}{5}=\frac{4}{3}\) \(-x-\frac{2}{7}=-\frac{8}{9}\)
\(x=\frac{4}{7}+\frac{3}{5}\) \(x=\frac{4}{3}-\frac{3}{5}\) \(-x=-\frac{8}{9}+\frac{2}{7}\)
\(x=\frac{41}{35}\) \(x=\frac{11}{15}\) \(-x=-\frac{38}{63}\)
\(x=\frac{38}{63}\)
\(\frac{7}{9}-x=\frac{1}{5}\)
\(x=\frac{7}{9}-\frac{1}{5}\)
\(x=\frac{26}{45}\)
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\Leftrightarrow\frac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
\(\Leftrightarrow\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
\(\Leftrightarrow\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{13}.3^{13}-2^{11}.3^{11}}\)
\(\Leftrightarrow\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.2^{12}-2^{11}.2^{11}}\)
\(\Leftrightarrow\frac{2^{12}.3^{10}.\left(1+5\right)}{6^{12}-6^{11}}\)
\(\Leftrightarrow\frac{2^{12}.3^{10}.6}{6^{11}.\left(6-1\right)}\)
\(\Leftrightarrow\frac{2^{12}.3^{10}.2.3}{6^{11}.\left(6-1\right)}\)
\(\Leftrightarrow\frac{2^{13}.3^{11}}{6^{11}.5}\)
\(\Leftrightarrow\frac{2^{11}.3^{11}.2^2}{6^{11}.5}\)
\(\Leftrightarrow\frac{6^{11}.4}{6^{11}.5}\Leftrightarrow\frac{4}{5}\)
46 . 95 + 69 . 120 / 84 . 312 - 611
= ( 22 )6. ( 32 ) 5 + (2 . 3 ) 9 . 23 . 3 . 5 / ( 23 ) 4 . 312 - ( 2 . 3 ) 11
= 2^12.3^10+2^9.3^9.2^3.3.5 / 2^12.3^12-2^11.3^11
= 2^12.3^10+2^12.3^10.5 / 2^11.3^11.(2.3-1)
= 2^12.3^10.(1+5) / 2^11.3^11. (6-1)
= 2^12.3^10.6 / 2^11.3^11.5
= 2^13.3^11 / 2^11.3^11.5
= 2^2/5
=4/5
\(-\left(1+2+3+...+2018\right)\)
\(1+2+3+...+2018=\left[\left(2018-1:1+1\right).\left(2018+1\right):2\right]\)
\(=\frac{2018.2019}{2}=1009.2019\)
\(=>-\left(1+2+...+2018\right)=-\left(1009.2019\right)\)
bằng bao nhiêu bn tự tính nha
= -2037171