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nhớ h cho mình nha .
\(\frac{1}{1.3.7}+\frac{1}{3.7.9}+\frac{1}{7.9.13}+\frac{1}{9.13.15}+\frac{1}{13.15.19}\)=
\(\frac{1}{6}\left(\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{7.3}-\frac{1}{9.7}+....+\frac{1}{13.15}-\frac{1}{15.19}\right)\)
\(=\frac{1}{6}\left(\frac{1}{1.3}-\frac{1}{15.19}\right)\)
\(=\frac{1}{6}.\frac{94}{285}\)
\(=\frac{47}{855}\)
mình chắc nó đúng nhưng thấy số to quá nên mình sợ sai
A = \(\dfrac{4}{3}\) + \(\dfrac{17}{3}\) + \(\dfrac{17}{9}\) + \(\dfrac{19}{13}\) + \(\dfrac{1}{9}\) + \(\dfrac{14}{6}\)
A = (\(\dfrac{4}{3}\) + \(\dfrac{17}{3}\)) + (\(\dfrac{17}{9}\) + \(\dfrac{1}{9}\)) + (\(\dfrac{19}{13}\) + \(\dfrac{14}{6}\))
A = \(\dfrac{21}{3}\) + \(\dfrac{18}{9}\) + \(\dfrac{148}{39}\)
A = 7 + 2 + \(\dfrac{148}{39}\)
A = 9 + \(\dfrac{148}{39}\)
A = \(\dfrac{39\times9}{39}\) + \(\dfrac{148}{39}\)
A = \(\dfrac{499}{39}\)
a,7429-(3125+4297)
=7407-93103+4297)
=7407-7400
7
b,9/8-(17/7-3/7)+7/8
=(9/8 +7/8)-(17/7-3/7)
=2-2
=0
c,tự làm nhé..
a) = 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
b) = 1/3 x 4/5 + 1/3 x6/5 + 1/3 x 2 = 1/3(4/5 + 6/5 + 2) = 1/3 x 4 = = 4/3
c) 4/7 x 2/9 + 4/7 x 7/9 + 2/3 = 4/7 x (2/9 + 7/9) + 2/3 = 4/7 x 1 + 2/3 = 26/21
A) 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
B) 1/3 x 4/5 + 1/3 x 6/5 + 1/3 x 2 = 1/3 x(4/5 + 6/5 x 2 ) = 1/3 x 4 = 4/3
c) TƯƠNG TỰ CÂU A VÀ B
* HOKTOT*
NHA
a,
\(\frac{8}{3}+\frac{17}{9}+\frac{19}{13}+\frac{1}{3}+\frac{7}{13}+\frac{1}{9}\)
\(=\left(\frac{8}{3}+\frac{1}{3}\right)+\left(\frac{17}{9}+\frac{1}{9}\right)+\left(\frac{19}{13}+\frac{7}{13}\right)\)
\(=3+2+2\)
\(=7\)
1+1+868+9+562+19+374+965+776+9745
=(1+9)+(1+19)+(868+562)+(374+776)+(965+9745)
=10+20+1430+1150+10710=13320
\(=\left(1+9\right)+\left(1+19\right)+\left(868+562\right)+\left(374+776\right)+\left(965+9745\right)\)
\(=10+20+1430+1150+10710\)
\(=13320\)