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Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55
A = 10 ×( 2/11×13+2/13×15+...12/53×55)
A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)
A = 10 × (1/11-1/55)
A =10 × 4/55
A = 8/11
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(12000+X):376=X
12000+X=376 x X
12000=376 x X - X
12000=375 x X
X=12000:375= 32
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a) 2 x 12 x 43 + 3 x 32 x 8 + 25 x 6 x4
=(2 x12) x43+(3 x8) x32+(6 x4) x25
=24 x43+24 x32+ 24 x25
=24 x(43+32+25)
=24 x100
=2400
b) 78 x 31 + 78 x 24 + 17 x 78 + 28 x 78
=78x(31+24+17+28)
=78x100
=7800
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a) 81 + 243 + 19 = (81 + 19) + 243
= 100 + 143 = 243
b) 168 + 79 + 132 = (168 + 132) + 79
= 300 + 79 = 379
c) 5 x 25 x 2 x 16 x 4 = (5 x 2) x (25 x 4) x 16
= 10 x 100 x 16 = 16000
d) 32 x 47 + 32 x 53 = 32 x (47 + 53)
= 32 x 100 = 3200
e) 26 + 27 + 28 + 29 + 30 + 31 + 32 = (26 + 32) + (27 + 31) + (28 + 30) + 29
= 58 + 58 + 58 + 29
= 58 x 3 + 29 = 174 + 29 = 203
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a,[(4x+28):3+55]:5=35
(4x+28):3+55=175
(4x+28):3=120
4x+28=360
4x=332
x=83
a) [( 4x + 28 ) : 3 + 55] : 5 = 35
( 4x + 28 ) : 3 + 55 = 175
( 4x + 28 ) : 3 = 120
4x + 28 = 360
4x = 332
x = 83
b) \(\left(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+...+\frac{2}{19\cdot21}\right)\cdot x=\frac{9}{7}\)
\(\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{19}-\frac{1}{21}\right)\cdot x=\frac{9}{7}\)
\(\left(\frac{1}{3}-\frac{1}{21}\right)\cdot x=\frac{9}{7}\)
\(\frac{2}{7}\cdot x=\frac{9}{7}\)
\(x=\frac{9}{2}\)
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a) \(\left(15-x\right)+\left(x-12\right)=7-\left(-8+x\right)\)
\(15-x+x-12=7+8-x\)
\(x=12\)
b) \(x-\left\{55-\left[49+\left(-28-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)
\(x-55+49-28-x=13-47-25+32-x\)
\(x=7\)
\(a,\left(15-x\right)+\left(x-12\right)=7-\left(-8+x\right)\)
\(15-x+x-12=7+8-x\)
\(15-x=3\)
\(x=12\)
\(b,x-\left\{55-\left[49+\left(-28-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)
\(x-\left[55-\left(49-28-x\right)\right]=13-\left[47+\left(25-32+x\right)\right]\)
\(x-\left(55-49+28+x\right)=13-\left(47+25-32+x\right)\)
\(x-\left(34+x\right)=13-\left(40+x\right)\)
\(x-34-x=13-40-x\)
\(-27-x=-34\)
\(x=-27--34\)
\(x=7\)
\(c,\left|x-10\right|-\left|-12\right|=4\)
\(\left|x-10\right|-12=4\)
\(\left|x-10\right|=16\)
\(\Rightarrow x-10=16\)hoặc \(x-10=-16\)
\(x=26\)hoặc \(x=-6\)
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a/ 1+4+7+10+....+52+55+58-410=[(58-1):3+1]x(58+1)-410=20x59-410=770
1 + 1 = 2
2 x 28 = 56
433 - 55 = 378
=^_^=
k mình nha
1 + 1 = 2
2 x 28 = 56
32 : 3 = \(\frac{32}{3}\)
433 - 55 = 378