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Vì \(x,y\in z\Rightarrow3x-12;y-5\inƯ\left(7\right)=\left\{\mp1;\mp7\right\}\)
Ta có bảng sau:
3x-12 | 1 | -1 | 7 | -7 |
y-5 | 7 | -7 | 1 | -1 |
x | 13/3 | 11/3 | 19/3 | 5/3 |
y | 12 | -2 | 6 | 4 |
Vì \(x;y\in Z=>\left(x;y\right)\in\varnothing\)
Vậy \(\left(x;y\right)\in\varnothing\)
Bn cs thể ghi đề sai chăng?
x.(0,5-2/3)=7/12
x.-1/6 =7/12
x =7/12:-1/6
x = -7/2
k mk nha bạn!! thanks nhìu!!
\(a,-12.\left(x-5\right)+7.\left(-x+3\right)=5\)
\(-12x+60-7x+21=5\)
\(-19x+81=5\)
\(-19x=5-81\)
\(-19x=-76\)
\(x=4\)
\(b,30.\left(x+2\right)-6.\left(x-5\right)-24.x=100\)
\(30x+60-6x+30-24x=100\)
\(0x+90=100\)
\(0x=100-90\)
\(0x=10\)
=> ko có giá trị nào thõa mãn x
a) 1/2x - 2/3x = 7/12
-1/6x = 7/12
x = \(\frac{7}{12}\div\frac{-1}{6}\)
x = -7/2
b) x: 12 = -2,5
x = -2,5*12
x = -30
c) 11/2x = 13/15
x = 13/15:11/2
x = 26/165
d) 3x/7 + 1 = (-1/28)*(-4)
3x/7 + 1 = 1/7
3x/7 = 1/7 - 1
3x/7 = -6/7
3x = -6
x= -6/3
x= -2
a) x(0.5 - 2/3 ) = 7/12
(-1/6)x = 7/12
x = 7/12 : (-1/6)
x =-7/2
b) x : 12 = -2,5
x= -2.5 * 12 =-30
c) x = 13/15 : 5,5
x =26/125
d) 3x/7 + 1 = -1/28 * (-4)
3x/7 + 1 =1/7
3x/7 = 1/7 -1
3x/7 =-6/7
3x =-6/7 * 7
3x = -6
x =-2
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\(3.\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(3.\left(3x-\frac{1}{2}\right)^3=-\frac{1}{9}\)
\(3x-\frac{1}{2}^3=-\frac{1}{9}:3\)
\(\left(3x-\frac{1}{2}\right)^3=-\frac{1}{9}.\frac{1}{3}\)
\(\left(3x-\frac{1}{2}\right)^3=-\frac{1}{27}\)
\(\left(3x-\frac{1}{2}\right)^3=\left(-\frac{1}{3}\right)^3\)
\(\Rightarrow3x-\frac{1}{2}=-\frac{1}{3}\)
\(3x=-\frac{1}{3}+\frac{1}{2}\)
\(3x=-\frac{2}{6}+\frac{3}{6}\)
\(3x=\frac{1}{6}\)
\(x=\frac{1}{6}:3\)
\(x=\frac{1}{6}.\frac{1}{3}\)
\(x=\frac{1}{18}\)
Vậy \(x=\frac{1}{18}\)
0,5x-2/3x=7/12
x(0,5-2/3)=7/12
x(-1/6)=7/12
x=-7/2
=>-1/6x=7/12
=> x=-3,5
Ai h mk mk se h lai