giải hộ tôi: x+6/x+5 + 3/2 = 2
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x + 6 = y(x - 1)
=> x + 6 = xy - y
=> x - xy + y = -6
=> x(1 - y) -1 + y = -7
=> x(1 - y) - (1 - y) = -7
=> (x - 1)(1 - y) = -7
tự xét bảng
b, tương tự
;x+6=y(x-1)
y ( x - 1 ) - x = 6
y ( x - 1 )- x + 1 = 7
y ( x - 1 ) - ( x x - 1 ) = 7
( y - 1 ) ( x - 1 ) = 7

a,(x+1)-(x+2)-(x+3)=24
=>x+1-x-2-x-3 =24
=>(x-x-x)+(1-2-3) =24
=> -x-4 =24
=> -x =24+4
=> -x =28
=> x =-28
Vậy x=-28
b,4x+2-3(x-1)=3x-5
=>4x+2-3x+3=3x-5
=>3x-4x+3x =2+3+5
=>2x =10
=>x =5
Vậy x=5
c,x-1-2(x-2)=x-11
=>x-1-2x+4=x-11
=>x-2x-x =-11+1-4
=>-2x =-14
=>x =7
Vậy x = 7

\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3=\frac{1}{5}-x\)
\(\left(3x-5x\right)-\left(\frac{3}{2}+3\right)=\frac{1}{5}-x\)
\(\left(-2\right).x-\frac{9}{2}=\frac{1}{5}-x\)
\(\left(-2\right).x+x.1=\frac{1}{5}+\frac{9}{2}\)
\(-1.x=\frac{47}{10}\)
\(x=\frac{47}{10}:\left(-1\right)\)
\(x=\frac{47}{10}.\frac{1}{-1}\)
\(x=\frac{47}{-10}\)
Vậy \(x=\frac{47}{-10}\)

\(x^2+2\left(x+1\right)^2+3\left(x+2\right)^2+4\left(x+3\right)^2=0\)
\(\Rightarrow x^2+2\left(x^2+2x+1\right)+3\left(x^2+4+4x\right)+4\left(x^2+6x+9\right)=0\)
\(\Rightarrow x^2+2x^2+4x+2+3x^2+12+12x+4x^2+24x+36=0\)
\(\Rightarrow10x^2+40x+50=0\)
\(\Rightarrow10\left(x^2+4x+5\right)=0\)
\(\Rightarrow x^2+4x+5=0\)
\(\Rightarrow\left(x^2+4x+2\right)+3=0\)
\(\Rightarrow\left(x+2\right)^2=-3\)
Mà \(\left(x+2\right)^2\ge0\)với mọi \(x\)
Vậy...

2/3 x X = 31/4 + 1/4
2/3 x X = 8
x = 8 : 2/3
x = 12
kq x =12 nha
tick cho mk vs

3 ( x + 2 ) - 6 ( x - 5 ) = 2 ( 5 - 2x )
3 ( x + 2 ) - 6 ( x - 5 ) - 2 ( 5 - 2x ) = 0
3x + 6 - 6x + 30 - 10 + 4x = 0
( 3x - 6x + 4x ) + ( 6 + 30 - 10 ) = 0
x + 26 = 0
x = - 26
Vậy x = -26
\(3\left(x+ 2\right)-6\left(x-5\right)=2\left(5-2x\right)\)
\(3\left(x+2\right)-6\left(x-5\right)-2\left(5-2x\right)=0\)
\(3x+6-6x+30-10+4x=0\)
\(\left(3x-6x-4x\right)+\left(6+30-10\right)=0\)
\(x+26=0\)
\(x=0-26\)
\(x=-26.\)
Vậy x = -26.
#Nguyên


a) \(x-17=19\)
\(\Leftrightarrow x=36\).
b) \(126⋮x,90⋮x,x>2\)
\(126⋮x,90⋮x\Rightarrow x\inƯ\left(ƯCLN\left(90,126\right)\right)\)
Ta có: \(126=2.3^2.7\), \(90=2.3^2.5\).
\(\RightarrowƯCLN\left(90,126\right)=2.3^2=18\).
\(\Rightarrow x\inƯ\left(18\right)\)mà \(x>2\)nên \(x\in\left\{3,6,9,18\right\}\).
lo
ĐKXĐ: x<>-5
Ta có: \(\frac{x+6}{x+5}+\frac32=2\)
=>\(\frac{x+6}{x+5}=2-\frac32=\frac12\)
=>2(x+6)=x+5
=>2x+12=x+5
=>2x-x=5-12
=>x=-7(nhận)