2^3 : 8 x ( 12^3 - 3^3 x 2^6 + 1284 )
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\(a,\Leftrightarrow\left[{}\begin{matrix}x-3=6\\x-3=-6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=9\\x=-3\end{matrix}\right.\)
Vậy ...
\(b,\Leftrightarrow\left|x\right|=12-8=4\)
\(\Leftrightarrow x=\pm4\)
Vậy ...
c, Xem lại đề nha bạn .
d, Thấy : \(\left(\dfrac{3}{4}-x\right)^2\ge0\)
Vậy phương trình vô nghiệm
a) |x - 3| = 6
\(\Rightarrow\left[{}\begin{matrix}x-3=6\\x-3=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=9\\x=-3\end{matrix}\right.\)
Vậy x = 9 hoặc x = - 3
b) 12 - |x| = 8
\(\Rightarrow\) |x| = 4
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
Vậy x = 4 hoặc x = - 4

nhiều quá :((
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(-x=45\)
\(x=45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36==12\)
\(3x=48\)
\(x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(3x-12-8+x=0\)
\(4x-20=0\)
\(4x=20\)
\(x=5\)
Cố nốt nha bn !
cảm ơn, bn nha:)))
mà hình như bạn TOP 3 trả lời câu hỏi pải ko nhỉ???

1) |x + 2| = 4
\(\Leftrightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=-6\end{cases}}\)
2) 3 – |2x + 1| = (-5)
\(\Leftrightarrow\left|2x+1\right|=8\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-9}{2}\end{cases}}\)
3) 12 + |3 – x| = 9
\(\Leftrightarrow\left|3-x\right|=-3\)(vô lí)
=>\(x=\varnothing\)
1) I x+2 I=4
\(\Rightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-6\end{cases}}}\)
2) \(3-|2x+1|=-5\)
\(\Leftrightarrow|2x+1|=8\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=7\\2x=-9\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-9}{2}\end{cases}}}\)
3) \(12+|3-x|=9\)
\(\Leftrightarrow|3-x|=-3\)(vô lí vì I 3-x I \(\ge\)0)

Ta có :1.2+2.4+3.6+4.8+5.10/3.4+6.8+9.12+12.16+15.20=[1.2(1+4+9+...+25)]/[3.4(1+4+9+16)]
=(1.2)/(3.4)=2/12=1/6
CHÚC BẠN HỌC TỐT!!
cho tớ nhé!!!!

Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)

) 2 x 6 = 12 3 x 7 = 21
12 : 2 = 6 21 : 3 = 7
12 : 6 = 2 21 : 7 = 3
4 x 8 = 32 5 x 9 = 45
32 : 4 = 8 45 : 5 = 9
32 : 8 = 4 45 : 9 = 5
b) 600 : 3 = 200 800 : 4 = 200 400 : 2 = 200
600 : 2 = 300 800 : 2 = 400 500 : 5 = 100
a) 2x6=12 3x7=21
12:2=6 21:3=7
12:6=2 21:7=3
4x8=32 5x9=45
32:4=8 45:5=9
32:8=4 45:9=5
b) 600:3=200 800:4=200 400:2=200
600:2=300 800:2=400 500:5=100
A Legend Never Dies

\(a,\frac{5}{6}-x=-\frac{7}{12}+\frac{2}{3}\)
\(\frac{5}{6}-x=\frac{1}{12}\)
\(x=\frac{5}{6}-\frac{1}{12}=\frac{3}{4}\)
\(b,\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)
\(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}=-\frac{1}{15}\)
\(x=\frac{1}{3}:-\frac{1}{15}=-5\)
\(c,\frac{8}{3}x+\frac{8}{3}=\frac{10}{3}\)
\(\frac{8}{3}.\left(x+1\right)=\frac{10}{3}\)
\(x+1=\frac{10}{3}:\frac{8}{3}=\frac{5}{4}\)
\(x=\frac{5}{4}-1=\frac{1}{4}\)
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{8}{12}\)
\(\frac{5}{6}-x=\frac{1}{12}\)
\(x=\frac{5}{6}-\frac{1}{12}\)
\(x=\frac{10}{12}-\frac{1}{12}\)
\(x=\frac{9}{12}=\frac{3}{4}\)

10( x - 4 ) - 8( x + 2 ) = 12
10x - 40 - 8x + 16 = 12
=> x( 10 - 8 ) - 40 + 16 = 12
2x - 40 + 16 = 12
2x - 40 = -4
2x = -4 + 40 = 36
x = 36 : 2 = 18
8.(x+2)-6.x=140
8( x + 2 ) - 6x = 140
8x + 16 - 6x = 140
x( 8 - 6 ) + 16 = 140
2x + 16 = 140
2x = 140 - 16
2x = 124
x = 124 : 2
x= 62
10.(x-4)-8.(x+2)=12
10x - 40 - 8x + 16 = 12
x( 10 - 8 ) - 40 + 16 = 12
2x - 40 + 16 = 12
2x - 40 = 12-16
2x - 40 = -4
2x = -4 + 40
2x = 36
x = 36 : 2
x= 18
x.(x-3)=6.(x-3)
`2^3:8xx(12^3-3^3xx2^6+1284)`
`=8:8xx[12^3-3^3xx(2^2)^3+1284)`
`=8:8xx[12^3-(3xx2^2)^3+1284]`
`=8:8xx[12^3-(3xx4)^3+1284]`
`=8:8xx(12^3-12^3+1284)`
`=8:8xx(0+1284)`
`=8:8xx1284`
`=1xx1284`
`=1284`
Vậy: `...`
2^3 : 8 x (12^3 - 3^3 x 2^6 + 1284)
= 1 x (1728 - 1728 + 1284)
= 1284