\(\frac{-6}{13}\cdot \frac{13}{21}+\frac{6}{13}.\frac{-8}{21}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a, \(\frac{6}{7}.\frac{16}{15}.\frac{7}{6}.\frac{21}{32}=\frac{6}{7}.\frac{7}{6}.\frac{16}{15}.\frac{21}{32}\)=\(1.\frac{16}{15}.\frac{21}{32}=\frac{7}{5.2}=\frac{7}{10}\)
Phần b T2
c,\(\frac{7}{4}.\frac{11}{21}+\frac{11}{21}.\frac{5}{4}=\frac{11}{21}.\left(\frac{7}{4}+\frac{5}{4}\right)\)=\(\frac{11}{21}.3=\frac{11}{7}\)

\(a,\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0.5-\frac{36}{21}\)
\(=\frac{11}{24}+\frac{13}{24}-\frac{5}{41}+\frac{1}{2}-\frac{36}{21}\)
\(=\frac{24}{24}-\frac{5}{41}+\frac{1}{2}-\frac{12}{7}\)
Số hơi to??
\(b,-12:\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
\(=-12:\left(\frac{9}{12}-\frac{10}{12}\right)^2\)
\(=-12:\left(-\frac{1}{12}\right)^2\)
\(=-12\cdot144\)
\(=-1728\)
\(a)=\left(\frac{11}{24}+\frac{13}{24}\right)-\left(\frac{5}{41}+\frac{36}{41}\right)+\frac{1}{2}\)
\(=\frac{24}{24}-\frac{41}{41}+\frac{1}{2}\)
\(=1-1+\frac{1}{2}\)
\(=\frac{1}{2}\)
\(y=\frac{4\frac{6}{11}x11\frac{8}{9}+4\frac{12}{13}:3\frac{2}{5}}{123\frac{34}{45}:21\frac{1}{8}}\)

Lời giải:
\(y=\frac{\frac{50}{11}.\frac{107}{9}+\frac{64}{13}.\frac{5}{17}}{\frac{5569}{45}.\frac{8}{169}}=\frac{1214030}{21879}:\frac{44552}{7605}=\frac{39455975}{4165612}\)

a ) \(\left(-\frac{40}{51}.0,32.\frac{17}{20}\right):\frac{64}{75}\)
\(=\left(-\frac{40}{51}.\frac{8}{25}.\frac{17}{20}\right):\frac{64}{75}\)
\(=\left(\frac{-40.8.17}{51.25.20}\right):\frac{64}{75}\)
\(=\left(\frac{-16}{75}\right).\frac{75}{64}\)
\(=\frac{-1}{1}.\frac{1}{4}=-\frac{1}{4}\)

\(\frac{13}{21}\)+ \(\frac{8}{21}\) : \(\frac{16}{21}\)
= \(\frac{13}{21}\)+ \(\left(\frac{8}{21}:\frac{16}{21}\right)\)= \(\frac{13}{21}\)+ \(\frac{1}{2}\)
= \(\frac{47}{42}\)
\(\frac{36}{35}\): \(\frac{8}{3}\)- \(\frac{36}{35}\): \(\frac{6}{11}\)
= \(\frac{27}{70}\)- \(\frac{66}{35}\)= \(-\frac{3}{2}\)

\(\frac{4}{9}:\frac{8}{9}-\frac{7}{13}:\frac{21}{13}\)
\(=\frac{4}{9}.\frac{9}{8}-\frac{7}{13}.\frac{13}{21}\)
\(=\frac{1}{2}-\frac{1}{3}\)
\(=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}\)
Ủng hộ tui nha! :)

a/ \(\frac{-9}{10}.\frac{5}{14}+\frac{1}{10}.\left(\frac{-9}{2}\right)+\frac{1}{7}.\left(-\frac{9}{10}\right)\)
= \(-\frac{9}{10}.\left(\frac{5}{14}+\frac{1}{7}\right)+\frac{1}{10}.\left(-\frac{9}{2}\right)\)
= \(-\frac{9}{10}.\frac{1}{2}+\frac{1}{10}.\left(-\frac{9}{2}\right)\)
= \(\frac{-9}{20}+\left(-\frac{9}{20}\right)=\frac{-18}{20}=\frac{-9}{10}\)
b/ \(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}+\frac{1}{11}\right).132\)
\(=\left(\frac{1}{2}.132\right)+\left(\frac{1}{3}.132\right)+\left(\frac{1}{4}.132\right)+\left(\frac{1}{6}.132\right)\)\(+\left(\frac{1}{11}.132\right)\)
\(=66+44+33+22+12=177\)
c/ \(-\frac{2}{3}.\left(\frac{8}{9}.\frac{8}{13}-\frac{8}{27}.\frac{8}{13}+\frac{4}{3}.\frac{22}{39}\right)\)
= \(-\frac{2}{3}.\left[\frac{8}{13}\left(\frac{8}{9}-\frac{8}{27}\right)+\frac{88}{117}\right]\)
= \(-\frac{2}{3}.\left(\frac{8}{13}.\frac{16}{27}+\frac{88}{117}\right)\)
= còn lại làm nốt nha! bận ròy
\(-\frac{6}{13}\cdot\frac{13}{21}+\frac{6}{13}\cdot\frac{-8}{21}=-\frac{6}{13}\cdot\frac{13}{21}+\frac{-6}{13}\cdot\frac{8}{21}\)
\(=-\frac{6}{13}\cdot\left(\frac{13}{21}+\frac{8}{21}\right)=-\frac{6}{13}\cdot\frac{21}{21}=-\frac{6}{13}\)
-6/13.13/21+6/13.(-8/21)
=-6/13.13/21+(-6/13).8/21
=-6/13.(13/21+8/21)
=-6/13.1 =-6/13