Cho 2 số nguyên m và n. Hãy tính tổng của N số nguyên tố nhỏ nhất và lớn hơn M. Pascal
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const fi='tep.inp';
fo='tep.out';
var f1,f2:text;
m,n,a:integer;
begin
assign(f1,fi); reset(f1);
assign(f2,fo); rewrite(f2);
readln(f1,m,n);
a:=m;
if a>n then a:=n;
kt:=0;
for i:=2 to trunc(sqrt(a)) do
if a mod i=0 then kt:=1;
if (kt=0) and (a>1) then writeln(f2,'so nho hon la so nguyen to')
else writeln(f2,'so nho hon khong la so nguyen to');
close(f1);
close(f2);
end.
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uses crt;
var n,i,dem,j,t:integer;
kt:boolean;
begin
clrscr;
readln(n);
t:=0;
for i:=2 to n do
begin
kt:=true;
for j:=2 to i-1 do
if i mod j=0 then kt:=false;
if kt=true then
begin
write(i:4);
t:=t+i;
end;
end;
writeln;
writeln(t);
readln;
end.
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Câu 1:
uses crt;
var n,i,t1,t2:integer;
begin
clrscr;
write('Nhap n='); readln(n);
t1:=0;
t2:=0;
for i:=1 to n do
begin
t1:=t1+i;
if i mod 2=0 then t2:=t2+i;
end;
writeln('Tong cac so tu 1 den ',n,' la: ',t1);
writeln('Tong cac so chan tu 1 den ',n,' la: ',t2);
readln;
end.
Câu 2:
uses crt;
var a,b,i,bcnn:longint;
begin
clrscr;
write('Nhap a='); readln(a);
write('Nhap b='); readln(b);
bcnn:=a*b;
for i:=a*b-1 downto 1 do
if (i mod a=0) and (i mod b=0) then
begin
if bcnn>i then bcnn:=i;
end;
writeln(bcnn);
readln;
end.
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uses crt;
var n,i:integer;
m:real;
begin
clrscr;
repeat
write('Nhap n='); readln(n);
until (1<=n) and (n<=30000);
m:=0;
for i:=1 to n do
m:=m+sqrt(i);
writeln('m=',m:4:2);
readln;
end.
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uses crt;
var a:array[1..250]of integer;
n,i,t,max,min:integer;
begin
clrscr;
write('Nhap n='); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
t:=0;
for i:=1 to n do
if a[i] mod 3=0 then t:=t+a[i];
writeln('Tong cac so la boi cua 3 la: ',t);
max:=a[1];
min:=a[1];
for i:=1 to n do
begin
if max<a[i] then max:=a[i];
if min>a[i] then min:=a[i];
end;
writeln('Gia tri lon nhat la: ',max);
writeln('Gia tri nho nhat la: ',min);
readln;
end.
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a) n mod 3=0;
b) m mod 7<>0;
c) y<=100;
d) (a+b>c) and (b+c>a) and (a+c>b);
e) ((a>0) and (b>0)) or ((a<0) and (b<0));
f) a/b=3/4;
g) ((a>5) and (b+c=10)) or ((a<=5) and (b+c=-20));
h) (m=1) or (m=3) or (m=5) or (m=7) or (m=8);
giúp với sắp nộp rồi
Program HOC24;
var m,n,i,d: integer;
t: longint;
function nt(x: integer): boolean;
var j: integer;
begin
nt:=true;
if (x=2) or (x=3) then exit;
nt:=false;
if (x=1) or (x mod 2=0) or (x mod 3=0) then exit;
j:=5;
while j<=trunc(sqrt(x)) do
begin
if (x mod j=0) or (x mod (j+2)=0) then exit;
j:=j+6;
end;
nt:=true;
end;
begin
write('Nhap m: '); readln(m);
write('Nhap n: '); Readln(n);
d:=0; i:=2;
while d<n do
begin
if nt(i) and (i>m) then
begin
d:=d+1;
t:=t+i;
end;
i:=i+1;
end;
write('Ket qua: ',t);
readln
end.