Question

[o0o I am a studious person o0o]

Cho \(a+b+c=0\)

Rút gọn : \(a^3+b^3+c\left(a^2+b^2\right)-abc\)

Answer 1

[Hoàng Lê Bảo Ngọc]

\(a+b+c=0\Leftrightarrow a+b=-c\) thay vào : 

\(a^3+b^3+c\left(a^2+b^2\right)-abc=\left(a+b\right)^3-3ab\left(a+b\right)+c\left[\left(a+b\right)^2-2ab\right]-abc\)

\(=-c^3-3ab.\left(-c\right)+c\left[c^2-2ab\right]-abc\)

\(=-c^3+3abc+c^3-2abc-abc=0\)

Answer 2

[Nguyễn Thị Mai Anh]

hello