Question

[๖ۣۜℳเйɦ☂đąйǥ☂ɦọς☂Ŧ๏áйッ]

A=1.2.3........100-1.2.3.....99-1.2.3.....99^2

Answer 1

[Lê Duy Khương]

\(A=1.2.3......100-1.2.3....99-1.2.3....99^2\)

    \(=1.2.3...99\left(100-1-99\right)\)

     \(=0\)

Answer 2

[Bellion]

                                               Bài làm :

Ta có :

\(A=1.2.3...100-1.2.3...99-1.2.3...99^2\)

\(A=\left(1.2.3...99\right)\left(100-1-99\right)\)

\(A=\left(1.2.3...99\right).0\)

\(A=0\)

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