Question

[Nam]

giúp mik với

Answer 1

[Trương Huy Hoàng]

Bài 1:

6, x - \(\frac{x+1}{3}\) = \(\frac{2x+1}{5}\)

\(\Leftrightarrow\) \(\frac{15x}{15}\) - \(\frac{5\left(x+1\right)}{15}\) = \(\frac{3\left(2x+1\right)}{15}\)

\(\Leftrightarrow\) 15x - 5(x + 1) = 3(2x + 1)

\(\Leftrightarrow\) 15x - 5x - 5 = 6x + 3

\(\Leftrightarrow\) 10x - 5 = 6x + 3

\(\Leftrightarrow\) 10x - 6x = 3 + 5

\(\Leftrightarrow\) 4x = 8

\(\Leftrightarrow\) x = 2

Vậy S = {2}

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Answer 2

[Lê Trang]

1) \(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}+2x\)

\(\Leftrightarrow\frac{9x+6}{6}-\frac{3x+1}{6}-\frac{10}{6}-\frac{12x}{6}=0\)

\(\Leftrightarrow\frac{9x+6-3x-1-10-12x}{6}=0\)

\(\Leftrightarrow\frac{-6x-5}{6}=0\)

\(\Leftrightarrow-6x-5=0\)

\(\Leftrightarrow-6x=5\Leftrightarrow x=-\frac{5}{6}\)

Vậy \(S=\left\{-\frac{5}{6}\right\}\)

2) \(\frac{x-3}{5}=6-\frac{1-2x}{3}\)

\(\Leftrightarrow\frac{3x-9}{15}-\frac{90}{15}+\frac{5-10x}{15}=0\)

\(\Leftrightarrow3x-9-90+5-10x=0\)

\(\Leftrightarrow-7x-94=0\)

\(\Leftrightarrow-7x=94\Leftrightarrow x=-\frac{94}{7}\)

Vậy \(S=-\frac{94}{7}\)