Question

[Nguyễn Giang]

Cho 2 số thỏa mãn . Giá trị

Answer 1

[Nguyễn Huy Tú]

\(\left(2x+1\right)^2+\left|y-1,2\right|=0\)

\(\Rightarrow\left(2x+1\right)^2=0\) và \(\left|y-1,2\right|=0\)

+) \(\left(2x+1\right)^2=0\Rightarrow2x+1=0\Rightarrow2x=-1\Rightarrow x=\frac{-1}{2}=-0,5\)

+) \(\left|y-1,2\right|=0\Rightarrow y-1,2=0\Rightarrow y=1,2\)

\(\Rightarrow x+y=\left(-0,5\right)+1,2=0,7\)

Vậy \(x+y=0,7\)