2015 x ( 1và3/4 ) = 2015
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\(1\frac{3}{7}\times1\frac{3}{10}\times1\frac{3}{13}\times...\times1\frac{3}{67}\)
\(=\frac{10}{7}\times\frac{13}{10}\times\frac{16}{13}\times...\times\frac{70}{67}\)
\(=\frac{10\times13\times16\times...\times70}{7\times10\times13\times...\times67}\)
\(=\frac{70}{7}=10\)
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2015 + 2015 x 2 + 2015 x 3 + 2015 x 4 = 2015 x ( 1 + 2 + 3 + 4 )
= 2015 x 10 = 20150
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a, (-x) = 2015^2015:2015^2015 => (-x) =1 => x=-1
b, x = 27 c, x = 2
^_^ Tick nhé ^_^
a, 20152015(-x)=20152015
=>20152015 :20152015=-x
=>1=-x
=>x=-1
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ta kó:
\(\frac{x-4}{2015}-\frac{1}{2015}=\frac{10-2x}{2015}\)
=>\(\frac{x-4-1}{2015}=\frac{10-2x}{2015}\)
=>x-5=10-2x
=>3x=15
=>x=5
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\(\frac{x-4-1}{2015}=\frac{10-2x}{2015}\)
=> x-4-1=10-2x
x+2x=10+4+1
3x=15
x=15/3
x=5
Vậy x=5
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Ta có: \(2015\cdot1\dfrac{3}{4}=2015\cdot\dfrac{7}{4}\)