Mười ba phần 18 trừ hai phần chín cộng một phần hai bằng bao nhiêu
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\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}=\frac{7}{2}+\frac{33}{7}-\frac{75}{14}=\frac{49}{14}+\frac{66}{14}-\frac{75}{14}=\frac{40}{14}=\frac{20}{7}\)
#Fox
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\(\frac{7}{13}.\frac{5}{9}+\frac{7}{19}.\frac{8}{13}-3.\frac{7}{19}=\)\(\frac{-1288}{2223}\)
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` 5/9 . ( -2/13)+5/9.(-7/13)+(-8/13) = 5/9(-2/13-7/13)-8/13=5/9.(-9/13)-8/13=-5/13-8/13=-13/13=-1 `
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\(\frac{7}{8}-\frac{7}{16}-\frac{11}{32}\)
= \(\frac{28}{32}-\frac{14}{32}-\frac{11}{32}\)
= \(\frac{28-14-11}{32}\)
= \(\frac{3}{32}\)
Đề : 7/8 - 7/16 - 11/32 = ?
Chọn MSC là 32 . Ta có phép tính : 28/32 - 14/32 - 11/32 = 3/32
Tíc nha !
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a; \(\dfrac{3}{5}\) - \(\dfrac{-7}{10}\) - \(\dfrac{13}{-20}\)
= \(\dfrac{12}{20}\) + \(\dfrac{14}{20}\) + \(\dfrac{13}{20}\)
= \(\dfrac{39}{20}\)
b; \(\dfrac{1}{2}\) + \(\dfrac{1}{-3}\) + \(\dfrac{1}{4}\) - \(\dfrac{-1}{6}\)
= \(\dfrac{6}{12}\) - \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{2}{12}\)
= \(\dfrac{7}{12}\)
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dễ, nhưng phai giai dc câu nay 60% nhan x cong 2 phan 3 = 1 phan 3 nhan 6va 1 phan 3
\(\frac{13}{18}-\frac{2}{9}+\frac{1}{2}\)
= \(\frac{13}{18}-\frac{4}{18}+\frac{9}{18}\)
= \(\frac{13-4+9}{18}\)
= \(\frac{18}{18}=1\)