Cho tam giác ABC có góc A vuông; cạnh AB = 40cm,cạnh AC = 60cm.EACD là hình thang có chiều cao =10cm(E ở trên BC;D nằm trên cạnh AB).Tính diện tích tam giác BED
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3:
góc C=90-50=40 độ
Xét ΔABC vuông tại A có sin C=AB/BC
=>4/BC=sin40
=>\(BC\simeq6,22\left(cm\right)\)
\(AC=\sqrt{BC^2-AB^2}\simeq4,76\left(cm\right)\)
1:
góc C=90-60=30 độ
Xét ΔABC vuông tại A có
sin B=AC/BC
=>3/BC=sin60
=>\(BC=\dfrac{3}{sin60}=2\sqrt{3}\left(cm\right)\)
=>\(AB=\dfrac{2\sqrt{3}}{2}=\sqrt{3}\left(cm\right)\)
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xét 2 tam giác vuông ABC và tam giác EDF, ta có:
cạnh góc vuông : AB = DE
góc nhọn : ABC = DEF
=> tam giác ABC = tam giác DEF ( cgv - gn )
Lý thuyết : Cạnh góc vuông - góc nhọn: Nếu một cạnh góc vuông và một góc nhọn kề cạnh ấy của tam giác vuông này bằng một cạnh góc vuông và một góc nhọn kề cạnh ấy của tam giác vuông kia thì hai tam giác đó bằng nhau (cgv-gn)
xét 2 tam giác vuông ABC và tam giác EDF, ta có:
cạnh góc vuông : AB = DE
góc nhọn : ABC = DEF
=> tam giác ABC = tam giác DEF ( cgv - gn )
Lý thuyết : Cạnh góc vuông - góc nhọn: Nếu một cạnh góc vuông và một góc nhọn kề cạnh ấy của tam giác vuông này bằng một cạnh góc vuông
và một góc nhọn kề cạnh ấy của tam giác vuông kia thì hai tam giác đó bằng nhau (cgv-gn)
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Ta có: <A+<B+<C=180
90+30+<C=180
<c=180-30-90=60
Xét ▲ABC và ▲MNP ta có:
<A=<M=90
<C=<P(=60)
Do đó ▲ABC đồng dạng ▲MNP(g-g)
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a: Xét ΔBAE vuông tại A và ΔBHE vuông tại H có
BE chung
góc ABE=góc HBE
=>ΔBAE=ΔBHE
b: Xét ΔEBC có góc EBC=góc ECB
nên ΔEBC cân tại E
mà EH là đường cao
nên H là trung điểm của BC
=>HB=HC
d: Xét ΔEAI vuông tại A và ΔEHC vuông tại H có
EA=EH
góc AEI=góc HEC
=>ΔEAI=ΔEHC
=>EI=EC>EH
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Cạnh AC dài \(10:\dfrac{1}{3}=30\left(cm\right)\)
Diện tích ABC là \(\dfrac{1}{2}\times30\times10=150\left(cm\right)\)
Diện tích hình tam giác ABC Là :
( 60 + 40 ) : 2 = 1200 ( cm2 )
Diện tích hình tam giác EAC là :
60 x 10 : 2 = 300 ( cm2 )
Diện tích tam giác ABE là :
1200 - 300 = 900 ( cm2 )
Độ dài của DE là :
( 90 x 2 ) : 40 = 45 ( cm )
Độ dài cạnh BD là :
40 - 10 = 30 ( cm )
Diện tích tam giác BED là :
30 x 45 : 2 = 675 ( cm2 )
đáp số : 675 cm2
^_^ chúc bạn học tốt nhé !!! ^_^
Diện tích tam giác ABC là: (60x40):2=1200cm vuông
Diện tích tam giác EAC là: 60x10:2=300 cm vuông
Diện tích tam giác ABE là: 1200-300=900 cm vuông
DE có số cm là: (90x2):40=45 cm
Cạnh BD dài số cm là: 40-10=30
Diện tích tam giác BED là: 30x45:2=675 cm vuông
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