
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


Gọi tử là : R
=> \(R=1+5+5^2+5^3+......+5^9\)
\(\Rightarrow5R=5+5^2+5^3+....5^{10}\)
\(\Rightarrow5R-R=5^{10}-1\)
\(\Rightarrow4R=5^{10}-1\)
\(\Rightarrow R=\frac{5^{10}-1}{4}\)
Goij mẫu là M
\(\Rightarrow M=1+5+5^2+5^3+.....+5^8\)
\(\Rightarrow5M=5+5^2+.....+5^9\)
\(\Rightarrow5M-M=5^9-1\)
\(\Rightarrow M=\frac{5^9-1}{4}\)
\(\Rightarrow A=\frac{\frac{5^{10}-1}{4}}{\frac{5^9-1}{4}}=1\)
Tương tự : B
Rồi so sánh thôi dễ mà
Phần B nek :
Gọi tử là : T
\(\Rightarrow T=1+3+3^2+.....+3^9\)
\(\Rightarrow3T=3+3^2+3^3+.....+3^{10}\)
\(\Rightarrow3T-T=3^{10}-1\)
\(\Rightarrow T=\frac{3^{10}-1}{2}\)
Gọi mẫu là : H
\(\Rightarrow H=1+3+3^2+.....+3^8\)
\(\Rightarrow3H=3+3^2+3^3+.....+3^9\)
\(\Rightarrow3H-H=3^9-1\)
\(\Rightarrow H=\frac{3^9-1}{2}\)
\(\Rightarrow B=\frac{T}{H}=\frac{\frac{3^{10}-1}{2}}{\frac{3^9-1}{2}}=\frac{29524}{9841}=3,0001.....\)
Cho a sửa câu a nha :
\(\Rightarrow A=\frac{R}{M}=\frac{\frac{5^{10}-1}{4}}{\frac{5^9-1}{4}}=\frac{2441406}{488281}=5,000002048\)
Vậy \(\Rightarrow A>B\left(đpcm\right)\)

a)(25.5-52.2):(5.2)-3
= (25.5-25.2):10-3
= 25.(5-2):10-3
= 25.3:10-3
=75:10-3=7,5-3=4,5
b)(6.52 -137).2-23.(7+3)(Sai đề)
c)23-53 :52 +12.22
= 8-125:25+12.4
= 8-5+12.4=8-5+48=3+48=51
d)2.[(95+52:5):22 +180] -22.102
= 2.[(95+25:5):4+180]-4.100
= 2.[(95+5):4+180]-400
= 2.(100:4+180)-400
= 2. (25+180)-400
= 2. 205-400
= 410-400=10
e)27.22+54:53.24-3.25
= 128+625:125.24-3.32
= 128+5.24-96
= 128+120-96
= 248-96=152
f)2.[(7-33 :32):22+99]-100
=2.[(7-27:9):4+99]-100
=2.[(7-3):4+99]-100
=2. (4:4+99)-100
=2. (1+99)-100
=2. 100-100
= 200-100
=100
Chúc Bạn Học Tốt ^_^

\(A=5+5^2+5^3+...+5^8\)
\(A=\left(5+5^2\right)+5^2\left(5+5^2\right)+...+5^6\left(5+5^2\right)\)
\(A=30+5^2.30+...+5^6.30\)
Vì 30\(⋮\)30
\(\Rightarrow A⋮30\)\(\Rightarrow A\in B\left(30\right)\)

Bài 1:
a) Ta có: \(\frac{3}{5}+\frac{4}{15}\)
\(=\frac{9}{15}+\frac{4}{15}\)
\(=\frac{13}{15}\)
b) Ta có: \(\frac{-3}{5}+\frac{5}{7}\)
\(=\frac{-21}{35}+\frac{25}{35}=\frac{4}{35}\)
c) Ta có: \(\frac{5}{6}:\frac{-7}{12}\)
\(=\frac{5}{6}\cdot\frac{-12}{7}=\frac{-60}{42}=\frac{-10}{7}\)
d) Ta có: \(\frac{-21}{24}:\frac{-14}{8}\)
\(=\frac{-7}{8}:\frac{-7}{4}\)
\(=\frac{-7}{8}\cdot\frac{4}{-7}=\frac{4}{8}=\frac{1}{2}\)
e) Ta có: \(\frac{-3}{5}\cdot\frac{5}{7}+\frac{-3}{5}\cdot\frac{3}{7}+\frac{-3}{5}\cdot\frac{6}{7}\)
\(=\frac{-3}{5}\left(\frac{5}{7}+\frac{3}{7}+\frac{6}{7}\right)\)
\(=-\frac{3}{5}\cdot2=\frac{-6}{5}\)
f) Ta có: \(\frac{1}{3}\cdot\frac{4}{5}+\frac{1}{3}\cdot\frac{6}{5}-\frac{4}{3}\)
\(=\frac{1}{3}\cdot\frac{4}{5}+\frac{1}{3}\cdot\frac{6}{5}-\frac{1}{3}\cdot4\)
\(=\frac{1}{3}\left(\frac{4}{5}+\frac{6}{5}-4\right)\)
\(=\frac{1}{3}\cdot\left(-2\right)=\frac{-2}{3}\)
g) Ta có: \(\frac{4}{19}\cdot\frac{-3}{7}+\frac{-3}{7}\cdot\frac{5}{19}+\frac{5}{7}\)
\(=\frac{4}{19}\cdot\frac{-3}{7}+\frac{5}{19}\cdot\frac{-3}{7}+\frac{-3}{7}\cdot\frac{5}{-3}\)
\(=-\frac{3}{7}\left(\frac{4}{19}+\frac{5}{19}+\frac{-5}{3}\right)\)
\(=\frac{-3}{7}\cdot\left(\frac{27}{57}+\frac{-95}{57}\right)\)
\(=\frac{-3}{7}\cdot\frac{-68}{57}=\frac{68}{133}\)
h) Ta có: \(\frac{5}{9}\cdot\frac{7}{13}+\frac{5}{9}\cdot\frac{9}{13}-\frac{5}{9}\cdot\frac{3}{13}\)
\(=\frac{5}{9}\left(\frac{7}{13}+\frac{9}{13}-\frac{5}{13}\right)\)
\(=\frac{5}{9}\)

a, \(B=\frac{19^{31}+5}{19^{32}+5}< \frac{19^{31}+5+90}{19^{32}+5+90}=\frac{19^{31}+95}{19^{32}+95}=\frac{19\left(19^{30}+5\right)}{19\left(19^{31}+5\right)}=\frac{19^{30}+5}{19^{31}+5}=A\)
b, Ta có: \(\frac{1}{A}=\frac{2^{20}-3}{2^{18}-3}=\frac{2^2.\left(2^{18}-3\right)+9}{2^{18}-3}=4+\frac{9}{2^{18}-3}\)
\(\frac{1}{B}=\frac{2^{22}-3}{2^{20}-3}=\frac{2^2\left(2^{20}-3\right)+9}{2^{20}-3}=4+\frac{9}{2^{20}-3}\)
Vì \(\frac{9}{2^{18}-3}>\frac{9}{2^{20}-3}\)\(\Rightarrow\frac{1}{A}>\frac{1}{B}\Rightarrow A< B\)
c, Câu hỏi của truong nguyen kim

a) 56 : 53 +33 . 32
=53+35
=125+243
=368
b)4.52 - 2 . 32
=4.25 - 2 . 9
=100 - 18
=82
1.66666666667 tick cho tui
\(\frac53\)