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14 tháng 9

Học lớp 4 thì sao

9 giờ trước (20:46)

Bài 5:

a: \(B=2009\cdot2011\)

\(=\left(2010-1\right)\left(2010+1\right)\)

\(=2010\cdot2010-1=A-1\)

=>B<A
b: \(B=2019\cdot2021\)

\(=\left(2020-1\right)\left(2020+1\right)\)

\(=2020\cdot2020-1\)

=A-1

=>B<A

c: \(A=234234\cdot233=234\cdot233\cdot1001\)

\(B=233233\cdot234=233\cdot234\cdot1001\)

Do đó: A=B

d: \(A=123\cdot137137=123\cdot137\cdot1001\)

\(B=137\cdot123123=137\cdot123\cdot1001\)

Do đó: A=B

Bài 4:

a: \(391-125<\overline{26x}<184+84\)

=>\(266<\overline{26x}<268\)

=>\(\overline{26x}=267\)

=>x=7

b: \(935+167<\overline{110x}<1240-135\)

=>\(1102<\overline{110x}<1105\)

=>x∈{3;4}

c: \(135\cdot12<\overline{162x}<4869:3\)

=>\(1620<\overline{162x}<1623\)

=>x∈{1;2}

d: \(11268:3<\overline{375x}<235\cdot16\)

=>\(3756<\overline{375x}<3760\)

=>x∈{7;8;9}

Bài 3:

l: x+125=492

=>x=492-125=367

m: 327-x=129

=>x=327-129=198

n: 124+(118-x)=217

=>118-x=217-124=93

=>x=118-93=25

o: 89-(73-x)=20

=>73-x=89-20=69

=>x=73-69=4

p: 198-(x+4)=120

=>x+4=198-120=78

=>x=78-4=74

q: (x+7)-25=23

=>x+7=25+23=48

=>x=48-7=41

r: 140:(x-8)=7

=>x-8=140:7=20

=>x=20+8=28

s: 4(x+41)=400

=>x+41=400:4=100

=>x=100-41=59

t: 4(3x-4)-2=18

=>4(3x-4)=2+18=20

=>3x-4=5

=>3x=9

=>x=3

u: 123-5(x+4)=38

=>5(x+4)=123-38=85

=>x+4=85:5=17

=>x=17-4=13

v: 231-(x-6)=1339:13

=>231-(x-6)=103

=>x-6=231-103=128

=>x=128+6=134

w: (x-36):18+12=14

=>(x-36):18=2

=>\(x-36=2\cdot18=36\)

=>x=36+36=72

8 giờ trước (21:14)

Bài 5:

a: \(B=2009\cdot2011\)

\(=\left(2010-1\right)\left(2010+1\right)\)

\(=2010\cdot2010-1=A-1\)

=>B<A
b: \(B=2019\cdot2021\)

\(=\left(2020-1\right)\left(2020+1\right)\)

\(=2020\cdot2020-1\)

=A-1

=>B<A

c: \(A=234234\cdot233=234\cdot233\cdot1001\)

\(B=233233\cdot234=233\cdot234\cdot1001\)

Do đó: A=B

d: \(A=123\cdot137137=123\cdot137\cdot1001\)

\(B=137\cdot123123=137\cdot123\cdot1001\)

Do đó: A=B

Bài 4:

a: \(391-125<\overline{26x}<184+84\)

=>\(266<\overline{26x}<268\)

=>\(\overline{26x}=267\)

=>x=7

b: \(935+167<\overline{110x}<1240-135\)

=>\(1102<\overline{110x}<1105\)

=>x∈{3;4}

c: \(135\cdot12<\overline{162x}<4869:3\)

=>\(1620<\overline{162x}<1623\)

=>x∈{1;2}

d: \(11268:3<\overline{375x}<235\cdot16\)

=>\(3756<\overline{375x}<3760\)

=>x∈{7;8;9}

Bài 3:

l: x+125=492

=>x=492-125=367

m: 327-x=129

=>x=327-129=198

n: 124+(118-x)=217

=>118-x=217-124=93

=>x=118-93=25

o: 89-(73-x)=20

=>73-x=89-20=69

=>x=73-69=4

p: 198-(x+4)=120

=>x+4=198-120=78

=>x=78-4=74

q: (x+7)-25=23

=>x+7=25+23=48

=>x=48-7=41

r: 140:(x-8)=7

=>x-8=140:7=20

=>x=20+8=28

s: 4(x+41)=400

=>x+41=400:4=100

=>x=100-41=59

t: 4(3x-4)-2=18

=>4(3x-4)=2+18=20

=>3x-4=5

=>3x=9

=>x=3

u: 123-5(x+4)=38

=>5(x+4)=123-38=85

=>x+4=85:5=17

=>x=17-4=13

v: 231-(x-6)=1339:13

=>231-(x-6)=103

=>x-6=231-103=128

=>x=128+6=134

w: (x-36):18+12=14

=>(x-36):18=2

=>\(x-36=2\cdot18=36\)

=>x=36+36=72

9 giờ trước (20:46)

Bài 5:

a: \(B=2009\cdot2011\)

\(=\left(2010-1\right)\left(2010+1\right)\)

\(=2010\cdot2010-1=A-1\)

=>B<A
b: \(B=2019\cdot2021\)

\(=\left(2020-1\right)\left(2020+1\right)\)

\(=2020\cdot2020-1\)

=A-1

=>B<A

c: \(A=234234\cdot233=234\cdot233\cdot1001\)

\(B=233233\cdot234=233\cdot234\cdot1001\)

Do đó: A=B

d: \(A=123\cdot137137=123\cdot137\cdot1001\)

\(B=137\cdot123123=137\cdot123\cdot1001\)

Do đó: A=B

Bài 4:

a: \(391-125<\overline{26x}<184+84\)

=>\(266<\overline{26x}<268\)

=>\(\overline{26x}=267\)

=>x=7

b: \(935+167<\overline{110x}<1240-135\)

=>\(1102<\overline{110x}<1105\)

=>x∈{3;4}

c: \(135\cdot12<\overline{162x}<4869:3\)

=>\(1620<\overline{162x}<1623\)

=>x∈{1;2}

d: \(11268:3<\overline{375x}<235\cdot16\)

=>\(3756<\overline{375x}<3760\)

=>x∈{7;8;9}

Bài 3:

l: x+125=492

=>x=492-125=367

m: 327-x=129

=>x=327-129=198

n: 124+(118-x)=217

=>118-x=217-124=93

=>x=118-93=25

o: 89-(73-x)=20

=>73-x=89-20=69

=>x=73-69=4

p: 198-(x+4)=120

=>x+4=198-120=78

=>x=78-4=74

q: (x+7)-25=23

=>x+7=25+23=48

=>x=48-7=41

r: 140:(x-8)=7

=>x-8=140:7=20

=>x=20+8=28

s: 4(x+41)=400

=>x+41=400:4=100

=>x=100-41=59

t: 4(3x-4)-2=18

=>4(3x-4)=2+18=20

=>3x-4=5

=>3x=9

=>x=3

u: 123-5(x+4)=38

=>5(x+4)=123-38=85

=>x+4=85:5=17

=>x=17-4=13

v: 231-(x-6)=1339:13

=>231-(x-6)=103

=>x-6=231-103=128

=>x=128+6=134

w: (x-36):18+12=14

=>(x-36):18=2

=>\(x-36=2\cdot18=36\)

=>x=36+36=72

NV
5 tháng 9

20.

a.

\(4^{n}=256\)

\(4^{n}=4^4\)

\(n=4\)

b.

\(9^{5n-8}=81\)

\(9^{5n-8}=9^2\)

5n-8=2

5n=10

n=2

c.

\(3^{n+2}:27=3\)

\(3^{n+2}=27.3\)

\(3^{n+2}=81\)

\(3^{n+2}=3^4\)

n+2=4

n=2

d.

\(8^{n+2}.2^3=8^5\)

\(8^{n+2}=8^5:2^3\)

\(8^{n+2}=8^4\)

n+2=4

n=2

NV
5 tháng 9

21.

a.

\(30-2x^2=12\)

\(2x^2=30-12\)

\(2x^2=18\)

\(x^2=18:2=9\)

\(x^2=3^2\)

\(x=\pm3\)

b.

\(\left(9-2x\right)^3=125\)

\(\left(9-2x\right)^3=5^3\)

\(9-2x=5\)

2x=9-5=4

x=2

c.

\(\left(2x-2\right)^4=0\)

2x-2=0

2x=2

x=1

d.

\(\left(x+5\right)^3=\left(2x\right)^3\)

x+5=2x

2x-x=5

x=5

6 tháng 9

20.

4^n=256

4^n=4^4

n=4


9^5n-8=81

9^5n-8=9^2

5n-8=2

5n=10

n=2


3^n+2:27=3

3^n+2:3^3=3

3^n+2-3=3

n+2-3=1

n=2


8^n+2.2^3=8^5

8^n+2.8=8^5

8^n+2+1=8^5

n+2+1=5

n=2


21.

30-2x^2=12

2x^2=30-12

2x^2=18

x^2=9

x^2=3^2

x=3


(9-2x)^3=125

(9-2x)^3=5^3

(9-2x)=5

2x=4

x=2


(2x-2)^4=0

(2x-2)=0

2x=2

x=1


(x+5)^3=(2x)^3

x+5=2x

x+5-2x=0

(x-2x)=-5

-x=-5

x=5

20:

a: \(4^{n}=256\)

=>\(4^{n}=4^4\)

=>n=4

b: \(9^{5n-8}=81\)

=>\(9^{5n-8}=9^2\)

=>5n-8=2

=>5n=10

=>n=2

c: \(3^{n+2}:27=3\)

=>\(3^{n+2}=27\cdot3=81=3^4\)

=>n+2=4

=>n=2

d: \(8^{n+2}\cdot2^3=8^5\)

=>\(8^{n+2}=8^5:8=8^4\)

=>n+2=4

=>n=2

Bài 21:

a: \(30-2x^2=12\)

=>\(2x^2=30-12=18\)

=>\(x^2=9\)

mà x>=0(do x là số tự nhiên)

nên x=3

b: \(\left(9-2x\right)^3=125\)

=>9-2x=5

=>2x=4

=>x=2

c: \(\left(2x-2\right)^4=0\)

=>2x-2=0

=>2x=2

=>x=1

d: \(\left(x+5\right)^3=\left(2x\right)^3\)

=>2x=x+5

=>2x-x=5

=>x=5

7 tháng 9

a) \(M=1+2+2^2+2^3+\cdots+2^{100}\)

\(2M=2+2^2+2^3+2^4+\cdots+2^{101}\)

\(2M-M=\left(2+2^2+2^3+2^4+\cdots+2^{101}\right)-\left(1+2+2^2+2^3+\cdots+2^{100}\right)\)

\(\Rightarrow M=2^{101}-1\)

Vậy \(M=2^{101}-1\)

b) \(N=1+3^2+3^4+3^6+\cdots+3^{100}\)

\(3N=3+3^2+3^4+3^6+3^8+\cdots+3^{102}\)

\(3N-N=\left(3+3^2+3^4+3^6+3^8+\cdots+3^{102}\right)-\left(1+3+3^2+3^4+3^6+\cdots+3^{100}\right)\)

\(\Rightarrow2N=3^{102}-1\)

\(\Rightarrow N=\frac{3^{102}-1}{2}\)

Vậy \(N=\frac{3^{102}-1}{2}\)

c) \(P=1+5^3+5^6+5^9+\cdots+5^{99}\)

\(5^3\cdot P=5^3+5^6+5^9+5^{12}\cdots+5^{102}\)

\(125P-P=\left(5^3+5^6+5^9+5^{12}\cdots+5^{102}\right)-\left(1+5^3+5^6+5^9+\cdots+5^{99}\right)\)

\(\Rightarrow124P=5^{102}-1\)

\(\Rightarrow P=\frac{5^{102}-1}{124}\)

Vậy \(P=\frac{5^{102}-1}{124}\)

a: \(M=1+2+2^2+\cdots+2^{100}\)

=>\(2M=2+2^2+2^3+\cdots+2^{101}\)

=>\(2M-M=2+2^2+2^3+\cdots+2^{101}-1-2-\cdots-2^{100}\)

=>\(M=2^{101}-1\)

b: \(N=1+3^2+3^4+\cdots+3^{100}\)

=>\(9N=3^2+3^4+3^6+\cdots+3^{102}\)

=>\(9N-N=3^2+3^4+\cdots+3^{102}-1-3^2-\cdots-3^{100}\)

=>\(8N=3^{102}-1\)

=>\(N=\frac{3^{102}-1}{8}\)

c: \(P=1+5^3+5^6+\cdots+5^{99}\)

=>\(125P=5^3+5^6+5^9+\cdots+5^{102}\)

=>\(125P-P=5^3+5^6+\cdots+5^{102}-1-5^3-\cdots-5^{99}\)

=>\(124P=5^{102}-1\)

=>\(P=\frac{5^{102}-1}{124}\)