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a) \(\left(x+3\right):4=12\)
\(x+3=12\cdot4\)
\(x+3=48\)
\(\Rightarrow x=45\)
b) 52015 : x = 52013
=> x = 52015 : 52013
=> x = 52
c) 21 + 3 . ( x - 7 ) = 72
3 . ( x - 7 ) = 72 - 21
3 . ( x - 7 ) = 51
x - 7 = 51 : 3
x - 7 = 17
=> x = 24

Ta có \(\frac{72-x}{7}-\frac{x-70}{9}=\frac{\left(72-x\right).9}{7.9}-\frac{\left(x-70\right).7}{9.7}=\frac{648-9x}{63}-\frac{7x-490}{63}\)
\(=\frac{648-9x-7x-490}{63}=\frac{158-2x}{63}\)

a)
(=)8x=64
(=)x=8
b)
(=) |x+3|=7
+) x+3=7
(=) x=4
+) x+3=-7
(=) x=-10
c)
(=) (x-7)2 = 9 = 32 =(-3)2
+) x-7=3
(=)x=10
+)x-7=-3
(=)x=4
#Note: sau mỗi câunhớ kết luận vs " Vậy x=... thì ( ghi lại đề)"
#Học-tốt

Tìm x biết:
\(\frac{x}{3}-\frac{3}{4}=\frac{1}{12}\)
\(\frac{x}{3}=\frac{1}{12}+\frac{3}{4}\)
\(\frac{x}{3}=\frac{5}{6}\)
\(x=\frac{5}{6}.3\)
\(x=\frac{5}{2}\)
Vậy \(x=\frac{5}{2}\)
\(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
\(\frac{13}{23}+x=\frac{29}{30}-\frac{7}{69}\)
\(\frac{13}{23}+x=\frac{199}{230}\)
\(x=\frac{199}{230}-\frac{13}{23}\)
\(x=\frac{3}{10}\)
Vậy \(x=\frac{3}{10}\)
Bài 2: tính
\(\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}\)
\(=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}\)
\(=\frac{1}{5}-\frac{1}{11}\)
\(=\frac{6}{55}\)
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{49.50}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{49}-\frac{1}{50}\)
\(=\frac{1}{1}-\frac{1}{50}\)
\(=\frac{49}{50}\)
Bài 2:
1/30+1/42+1/56+1/72+1/90+1/110
=1/5.6+1/6.7+1/7.8+1/8.9+1/9.10+1/10.11
=1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+1/10-1/11
=1/5-1/11=6/55
b)1/1.2+1/2.3+...+1/49.50
=1-1/2+1/2-1/3+...+1/49-1/50
=1-1/50
=49/50

a) 4x - 15 = - 75 - x
<=> 4x + x = -75 + 15
<=> 5x = -60
<=> x = -12
b) 72 - 3x = 5x + 8
<=> -3x -5x = 8 - 72
<=> -8x = -64
<=> x = 8
d) 3 . | x - 7 | = 21
<=> | x - 7 | = 7
\(\Leftrightarrow\orbr{\begin{cases}x-7=7\\x-7=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=14\\x=0\end{cases}}\)
\(-7\left|x+3\right|=-49\)
\(\Leftrightarrow\left|x+3\right|=7\)
\(\Leftrightarrow\orbr{\begin{cases}x+3=7\\x+3=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-10\end{cases}}\)

\(-12\left(x-5\right)+7\left(3+x\right)=55\)
\(\Rightarrow-12x+60+21+7x=55\)
\(\Rightarrow-5x+81=55\)
\(\Rightarrow-5x=55-81=-26\)
\(\Rightarrow x=\frac{26}{5}\)

a) 2.(x-5) - 3.(x+7) = 14
2.x - 10 - 3.x - 21 = 14
2.x - 3.x - (10+21) = 14
-x - 31 = 14
-x = 45
x = -45
phần b bn cx lm tương tự như phần a nha!
c) 5- (x+7) = 4
5 - x - 7 = 4
5-7 -x = 4
-2 -x = 4
x = -6
câu d lm giống câu c
a) 2.(x-5) - 3.(x+7) = 14
2.x - 10 - 3.x - 21 = 14
2.x - 3.x - (10+21) = 14
-x - 31 = 14
-x = 45
x = -45
12(x+7)−3(x+7)=72
(12−3)(x+7)=72⇒9(x+7)=72
x+7=8
x=1