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a) \(x=1000002;1000003;...;9999999\)
b) \(x=9999999\)
c) \(x=1000001;1000002\)
@#$%^&* !
a) x = 1 000 002
b) x = 9 999 999
c) x = 1 000 001 ; 1 000 002
k mik nha
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\(\frac{x}{7}x\frac{4}{9}x5=\frac{3x4x5}{7x9}\)
\(\frac{x}{7}x\frac{4}{9}x5=\frac{20}{21}\)
\(\frac{x}{7}x\frac{4}{9}=\frac{20}{21}:5\)
\(\frac{x}{7}x\frac{4}{9}=\frac{4}{21}\)
\(\frac{x}{7}\) \(=\frac{4}{21}:\frac{4}{9}\)
\(\frac{x}{7}\) \(=\frac{9}{21}\) \(=\frac{3}{7}\)
Vay x la 3
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\(\frac{x}{9}=\frac{8}{6}\Rightarrow\frac{x}{9}=\frac{4}{3}\Rightarrow x.3=9.4\Rightarrow x.3=36\Rightarrow x=36:3\Rightarrow x=12\)
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\(\Rightarrow28\left(x-9\right)=20.35\Rightarrow28x-252=700\Rightarrow28x=952\Rightarrow x=34\)
\(\frac{x-9}{35}=\frac{20}{28}=\frac{5}{7}=\frac{25}{35}\)
=>x-9=25
=>x=25+9
=>x=34
vậy x=34
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\(\frac{40-x}{9}=\frac{28}{36}\)
=> \(\frac{40-x}{9}=\frac{7}{9}\)
\(=>40-x=7\)
\(x=40-7\)
\(x=33\). Vậy x=33
mk khẳng định chắc chắn là 33
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a) \(x=6\times1000+3\times100+2\times10+8=6000+300+20+8=6328\)
b) \(x=5\times1000+6\times10+7=5000+60+7=5067\)
c) \(x=9\times1000+9\times100+9=9000+900+9=9909\)
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abc x 9 = 2abc
abc x 9= 2000+abc
abc x 9 - abc = 2000
abc x (9-1) = 2000
abc = 2000 : 8
abc = 250
2abc=9Xabc
2000+abc=9Xabc
2000=8Xabc ( cùng bớt ở 2 bên)
abc=2000:8
abc=250
vay abc=250
( 9 + x ) x 1000 = 6780000
9 + x = 6780000 : 1000
9 + x = 6780
x = 6780 - 9
x = 6771
(9 + x) \(\times\) 1000 = 678000
(9 + x) = 678000 : 1000
(9 + x) = 678
x = 678 - 9
x = 669
Vậy x=669.