tim x :
a, x/9 <7/x<x/6
b, 3/x < x/7 <4/x
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a) \(\dfrac{x}{15}\)=\(\dfrac{x-2}{30}\)
=>30x=15 (x-2)
=>30x=15x-30
=>30x-15x=-30
=>15x =-30
=>x =-2
b)\(\dfrac{7}{8}\)<\(\dfrac{x}{80}\)<\(\dfrac{9}{10}\)
=>\(\dfrac{70}{80}\)<\(\dfrac{x}{80}\)<\(\dfrac{72}{80}\)
=> 70<x<72
=>x=71
c)\(\dfrac{1}{6}\)<\(\dfrac{5}{x}\)<\(\dfrac{1}{4}\)
=>\(\dfrac{5}{30}\)<\(\dfrac{5}{x}\)<\(\dfrac{5}{20}\)
=>20<x<30
=>x={21;22;23;24;25;26;27;28;29}
a: x/7=9/y
nên xy=63
mà x>y
nên \(\left(x,y\right)\in\left\{\left(63;1\right);\left(21;3\right);\left(9;7\right);\left(-1;-63\right);\left(-3;-21\right);\left(-7;-9\right)\right\}\)
b: -2/x=y/6
nên xy=-12
mà x<0<y
nên \(\left(x,y\right)\in\left\{\left(-12;1\right);\left(-6;2\right);\left(-4;3\right);\left(-3;4\right);\left(-2;6\right);\left(-1;12\right)\right\}\)
\(\frac{7}{9}+\frac{16}{48}< x< \frac{43}{8}+0.125\)
\(\frac{10}{9}< x< \frac{11}{2}\)
\(1.11< x< 5.5\)
Vậy \(x=2;3;4;5.\)