289-11× (X-3) = 69. Tìm x
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a: =>3x=10+14=24
=>x=8
b: =>25-30-x=-19
=>-5-x=-19
=>x+5=19
=>x=14
c: =>15-x=12+14=26
=>x=-11
d: =>4x+11-x-34=67
=>3x-23=67
=>3x=90
=>x=30
e: =>-x-14=289-36-289=-36
=>x+14=36
=>x=22
a) 3x=24
x=8
b) 25-30-x=-19
25-30+19=x
14=x
c) 15-x=26
x=-11
d) 4x+11-x-34=67
3x=90
x=30
e) -14-x= -36
x=-14 -36
x= 22
Sao ban chui ban ay?
3-(17-x)=289-(36+289)
3-(17-x)=-36
17-x=-36+3
17-x=39
x=17-39
x=-22
Nho cho mk nhe!!!!!!
3-(17-x)=289-(36+289)
3-(17-x)=-36
17-x=39
x=17-39
x=-22
Vay x=-22
Nho cho mk 1 h nha!!!
de thui
nhung bây giờ mk bận
nên ko giải hộ bn được
chúc bn hoc tốt!
hihi
a.
\(3-\left(17-x\right)=289-\left(36+289\right)\)
\(3-17+x=289-36-289\)
\(x=\left(289-289\right)+\left(-36-3+17\right)\)
\(x=-22\)
b.
\(x-73=\left(-35\right)+\left|-55\right|\)
\(x-73=-35+55\)
\(x=-35+55+73\)
\(x=93\)
c.
\(\left|x\right|-3=2\)
\(\left|x\right|=3+2\)
\(\left|x\right|=5\)
\(x=\pm5\)
Vậy x = 5 hoặc x = -5
d.
\(\left|x+1\right|=5\)
\(x+1=\pm5\)
TH1:
\(x+1=5\)
\(x=5-1\)
\(x=4\)
TH2:
\(x+1=-5\)
\(x=-5-1\)
\(x=-6\)
Vậy x = 4 hoặc x = -6
a, \(3-17+x=289-36-289\)
\(\Rightarrow x-14=-36\)
\(\Rightarrow x=-22\)
\(b,x-73=\left(-35\right)+\left|-55\right|\)
\(\Rightarrow x-73=\left(-35\right)+55\)
\(\Rightarrow x-73=20\)
\(\Rightarrow x=93\)
\(c,\left|x\right|-3=2\)
\(\Rightarrow\left|x\right|=5\)
\(\Rightarrow x=\pm5\)
\(d,\left|x+1\right|=5\)
\(\Rightarrow\) \(\left[\begin{array}{nghiempt}x+1=5\\x+1=-5\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=4\\x=-6\end{array}\right.\)
3-(17-x)=289-(36+289)
<=> 3-17+x=289-36-289
<=> -14+x=-36 => x=-22
25-(x+5)=-45-(15-45)
<=> 25-x-5=-45-15+45
<=> 20-x=-15=> x=35
34-(21-x)=(3747-30)-3747
<=> 334-21+x=3747-30-3747
<=> 313+x=-30=> x=-343
3 - ( 17 - x ) = 289 - ( 36 + 289 )
3 - 17 + x = 289 - 36 - 289
- 14 + x = - 36
x = ( - 36 ) - ( - 14 )
x= - 22
25 - ( x + 5 ) = - 45 - ( 15 - 45)
25 - x - 5 = - 45 - 15 + 45
20 - x = - 15
x = 20 - ( - 15 )
x = 35
34 - ( 21 - x ) = ( 3747 - 30 ) - 3747
34 - 21 + x = 3747 - 30 - 3747
13 + x = - 30
x = ( - 30 ) - 13
x = - 46
\(B=\left(x-3\right)^2+\left(x-11\right)^2\)
\(=x^2-6x+9+x^2-22x+121\)
\(=2\left(x^2-14x+49\right)+32\)
\(=2\left(x-7\right)^2+32\)
Ta có: \(\left(x-7\right)^2\ge0\Leftrightarrow2\left(x-7\right)^2+32\ge32\)
Vậy \(MinB=32\Leftrightarrow x=7\)
\(C=\left(x+1\right)\left(x-2\right)\left(x-3\right)\left(x-6\right)\)
\(=\left(x+1\right)\left(x-6\right)\left(x-2\right)\left(x-3\right)\)
\(=\left(x^2-5x-6\right)\left(x^2-5x+6\right)\)
Đặt \(c=x^2-5x\)lúc này \(C\)thành: \(C=\left(c-6\right)\left(c+6\right)=c^2-36\)
Mà: \(c^2\ge0\forall c\Leftrightarrow c^2-36\ge-36\Leftrightarrow C\ge-36\)
Dấu '' = '' xảy ra: \(c=0\)
\(\Leftrightarrow x^2-5x=0\)
\(\Leftrightarrow x\left(x-5\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-5=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=5\end{cases}}\)
Vậy \(MinC=-36\Leftrightarrow\orbr{\begin{cases}x=0\\x=5\end{cases}}\)
289-11× (X-3) = 69
11× (X-3) =289-69=220
X-3=220:11=20
x=20+3=23
**** nhé
X = 23
*** cai nha !