107 mũ 50 và 73 mũ 75
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
so sánh
a) 9920 và 999910
Ta có: 9920=(992)10=980110
Vì 9801<9999
=> 980110<999910
Vậy 9920<999910
![](https://rs.olm.vn/images/avt/0.png?1311)
a,
15^12=(3*5)^12=3^12*5^12
81^3*125^5=(3^4)^3*(5^3)^5=3^12*5^15
Vì 12<15 suy ra 5^12<5^15
Suy ra 3^12*5^12<3^12*5^15
\(a.81^3.125^5=\left(3^4\right)^3.\left(5^3\right)^5=3^{12}.5^{15}=3^{12}.5^{12}.5^3=\left(3.5\right)^{12}.5^3=15^{12}.5^3>15^{12}\)
\(b.4^{20}.81^{12}=\left(2^2\right)^{20}.\left(9^2\right)^{12}=2^{40}.9^{24}=2^{20}.2^{20}.9^{20}.9^4=\left(2.9\right)^{20}.2^{20}.9^4=18^{20}.2^{20}.9^4>18^{20}\)
\(c.73^{75}=\left(73^3\right)^{25}=389017^{25}\)
\(107^{50}=107^{2.50}=\left(107^2\right)^{25}=11449^{25}\)
Vì \(389017^{25}>11449^{25}\Rightarrow73^{75}>107^{50}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$107^{50}=(107^2)^{25}=11449^{25}$
$73^{75}=(73^3)^{25}=389017^{25}$
$\Rightarrow 107^{50}< 73^{75}$
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(71^{50}< 81^{50}=3^{200}\)
\(37^{75}>27^{75}=3^{225}\)
vì \(71^{50}< 3^{200}< 3^{225}< 37^{75}\)=>\(71^{50}< 37^{75}\)
Ta có: \(107^{50}=\left(107^2\right)^{50}=11499^{25};73^{75}=\left(73^3\right)^{25}=389017^{25}\)
Mà \(11499<389017\)
Nên \(107^{50}<73^{75}\)