1×1×83×24+83
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a) 24 + 17 + 26 = (24 + 26) + 17
= 50 + 17
= 67
b) 80 + 310 + 120 + 90 = (80 + 120) + (310 + 90)
= 200 + 400
= 600
c) 34 + 140 + 60 + 16 = (34 + 16) + (140 + 60)
= 50 + 200
= 250
`@` `\text {Ans}`
`\downarrow`
`2023 \times 14 + 2023 \times 83+97`
`= 2023 \times (14+83) + 97`
`= 2023 \times 97 + 97`
`= 196231 +97`
`= 196328`
`78 \times 31+78 \times 24+78 \times 17+78 \times 22 \times 72`
`= 78 \times (31+24+17+22 \times 72)`
`= 78 \times (31+24+17+1584)`
`= 78 \times 1656`
`= 129168`
`371 \times 69+371 \times 14+629 \times 83`
`= 371 \times (69+14) + 629 \times 83`
`= 371 \times 83 + 629 \times 83`
`= 83 \times (371+629)`
`= 83 \times 1000`
`= 83000`
`91 \times 51+49 \times 163-49 \times 72`
`= 91 \times 51 + 49 \times (163-72)`
`= 91 \times 51+49 \times 91`
`= 91 \times (51+49)`
`= 91 \times 100`
`= 9100`
`3 \times 12 \times 17 + 4 \times 9 \times 81 + 2 \times 6 \times 6`
`= 9 \times 4 \times 17 + 4 \times 9 \times 81 + 4 \times 9 \times 2`
`= 9 \times 4 \times (17+81+2)`
`= 36 \times 100`
`= 3600`
`42 \times 17 + 58 \times 83 \times 42 \times 83 + 42 \times 83 + 17`
`= 17 \times (42+58) + 42 \times 83 \times (58 \times 83 +1)`
`= 17 \times 100 + 3486 \times 4815`
`= 1700 + 16785090`
`= 16786790`
48 . (-64) + 24. 66 - 48.( 83 - 64)
= 48 . ( - 64 ) + 24 . 66 - 48 . 83 - 48 . 64
= 48 . ( - 64 - 83 - 64 ) +24 . 66
= 48 . ( - 211 ) + 24 . 66
= - 10128 + 1584
= - 8544
a) 57 + 28 = 85
24 + 67 = 91
46 + 39 = 85
b) 83 - 19 = 64
42 - 38 = 4
90 - 76 = 14
\(\begin{array}{*{20}{c}}{a)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{57}\\{28}\end{array}}\\\hline{\,\,\,\,85}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{24}\\{67}\end{array}}\\\hline{\,\,\,\,91}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{46}\\{39}\end{array}}\\\hline{\,\,\,\,85}\end{array}\)
\(\begin{array}{*{20}{c}}{b)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{83}\\{19}\end{array}}\\\hline{\,\,\,\,64}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{42}\\{38}\end{array}}\\\hline{\,\,\,\,04}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{90}\\{76}\end{array}}\\\hline{\,\,\,\,14}\end{array}\)
a) Vì \(\dfrac{1}{24}< \dfrac{1}{83}\)
⇒ \(\dfrac{1}{24^9}>\dfrac{1}{83^{13}}\)
a) \(\left(\dfrac{1}{24}\right)^9>\left(\dfrac{1}{27}\right)^9=\dfrac{1}{3^{27}}\)
\(\left(\dfrac{1}{83}\right)^{13}< \left(\dfrac{1}{81}\right)^{13}=\dfrac{1}{3^{52}}\)
Mà \(\dfrac{1}{3^{27}}>\dfrac{1}{3^{52}}\)
\(\Rightarrow\left(\dfrac{1}{24}\right)^9>\left(\dfrac{1}{83}\right)^{13}\)
b) \(3^{300}=\left(3^3\right)^{100}=27^{100}\)
\(5^{199}< 5^{200}=\left(5^2\right)^{100}=25^{100}\)
Mà \(25^{100}< 27^{100}\)
\(\Rightarrow5^{199}< 3^{300}\)
\(\Rightarrow\dfrac{1}{5^{199}}>\dfrac{1}{3^{300}}\)
1×1×83×24+83
= 1x83x24+83
= 83x24+83
= 83x24+83x1
= 83x(24+1)
= 83x25
=
= 2075 nha