TÌM SỐ TỤ NHIÊN N+3 CHIA HẾT CHO 5
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Theo đề bài, a chia 2 dư 1 và chia 5 dư 1 => a có chữ số tận cùng là 1
Vì a nhỏ nhất và chia hết cho 9 và chia 7 dư 3 => a = 171
gọi so phải tìm là X
Theo đề bài ta co X+2 chia hết cho 3,4,5,6
suy ra X+2 là bội chung của 3,4,5,6
VCNN{3;4;5;6}=60 nên X+2=60.N
Do đó X=60.N-2{N=1;2;3;4...}
mặt khác X chia hết cho 11 lần lượt cho n = 1;2;3...
Ta thấy N=7 thì x=418 chia hết cho 11
vậy số nhỏ nhất phả tìm là 418
1)2n+5-2n-1
=>4 chia hết cho 2n-1
ước của 4 là 1 2 4
2n-1=1=>n=.....
tiếp với 2 và 4 nhé
Để n + 1 chia hết cho 5
\(\Rightarrow n+1\inƯ\left(5\right)\)
\(\Rightarrow n+1\in\left\{-1;1;-5;5\right\}\)
\(\Rightarrow n+1=-1\Rightarrow n=-2\)
\(\Rightarrow n+1=1\Rightarrow n=0\)
\(\Rightarrow n+1=-5\Rightarrow n=-6\)
\(\Rightarrow n+1=5\Rightarrow n=4\)
\(a,\Rightarrow n+3\inƯ\left(5\right)=\left\{-5;-1;1;5\right\}\\ \Rightarrow n\in\left\{-8;-4;-2;2\right\}\\ b,\Rightarrow n+3+5⋮n+3\\ \Rightarrow5⋮n+3\\ \Rightarrow n+3\inƯ\left(5\right)=\left\{-5;-1;1;5\right\}\\ \Rightarrow n\in\left\{-8;-4;-2;2\right\}\\ c,\Rightarrow2\left(2n-1\right)-3⋮2n-1\\ \Rightarrow3⋮2n-1\\ \Rightarrow2n-1\inƯ\left(3\right)=\left\{-3;-1;1;3\right\}\\ \Rightarrow n\in\left\{-1;0;1;2\right\}\\ d,\Rightarrow8-n+4⋮8-n\\ \Rightarrow4⋮8-n\\ \Rightarrow8-n\inƯ\left(4\right)=\left\{-4;-2;-1;1;2;4\right\}\\ \Rightarrow n\in\left\{12;10;9;7;6;4\right\}\)
We will have the opportunity to get the job And then we can
đó là những gì Lê Đình Thanh Phong nói.