a| 19.64+19.37-19
b| 45.12+13.55
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a: \(=100\cdot104=10400\)
d: \(=2\cdot9+4\cdot27=18+108=126\)
19.64 + 76.34
= 19.64 + 19.4.34
= 19.64 + 19.136
= 19.(64+136)
= 19.200
= 3800
65.(-19) + (-19).24 + (-19).11
= ( - 19) . ( 65 + 24 + 11 )
= ( -19) . 100 = -1900
`#3107.101107`
`15 - 203 - (-203)`
`= 15 - 203 + 203`
`= 15 - (203 - 203)`
`= 15`
____
`(-3)*(-19) + 3*(-30-19)`
`= (-3)*(-19) - 3*30 - 3*19`
`= (-3)*(-19 + 30 + 19)`
`= (-3)*30`
`= -90`
\(24\cdot(34-19)-34\cdot(24-19)\)
\(=24\cdot34-24\cdot19-34\cdot24-34\cdot19\)
\(=(24\cdot34-34\cdot24)-(24\cdot19-34\cdot19)\)
\(=0-(-190)=190\)
a: \(\dfrac{3}{5}-\dfrac{7}{4}=\dfrac{12}{20}-\dfrac{35}{20}=\dfrac{-23}{20}\)
b: \(\dfrac{4}{5}:\dfrac{-8}{15}=\dfrac{-4}{5}\cdot\dfrac{15}{8}=\dfrac{-60}{40}=\dfrac{-3}{2}\)
c: \(=7+\dfrac{5}{9}-2-\dfrac{3}{4}-3-\dfrac{5}{9}=2-\dfrac{3}{4}=\dfrac{5}{4}\)
d: \(=\dfrac{-3}{7}\left(\dfrac{4}{19}+\dfrac{15}{19}\right)+\dfrac{5}{7}=\dfrac{2}{7}\)
\(=\dfrac{4}{19}\left(\dfrac{-5}{6}-\dfrac{7}{12}-\dfrac{10}{3}\right)\)
\(=\dfrac{4}{19}\cdot\left(\dfrac{-10-7-40}{12}\right)=\dfrac{4}{19}\cdot\dfrac{-57}{12}=-\dfrac{3}{3}=-1\)
=\(\dfrac{4}{19}.\left(-\dfrac{5}{6}+-\dfrac{7}{12}\right)-\dfrac{40}{57}\)
=\(-\dfrac{4}{19}-\dfrac{40}{57}\)
=\(-\dfrac{52}{57}\)
`19.64 + 19.37 - 19`
`= 19.64 + 19.37 - 19.1`
`= 19.(64 + 37 - 1)`
`= 19 . 100`
`= 1900`
`45.12 + 13.55`
`= 45 . 12 + (1+12).55`
`= 45 . 12 + 55 + 12.55`
`= 12 . (45 + 55) + 55`
`= 12 . 100 + 55`
`=1200 + 55`
`=1255`
a: \(19\cdot64+19\cdot37-19\)
\(=19\left(64+37-1\right)\)
\(=19\cdot100=1900\)
b: \(45\cdot12+13\cdot55\)
\(=540+715\)
=1255