Tính A= \(\frac{9}{4x5}+\frac{9}{5x6}+.....+\frac{9}{35x36}\)
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BD
4
NN
Nguyễn Ngọc Anh Minh
CTVHS
VIP
11 tháng 10 2016
\(A=9\left(\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}+...+\frac{1}{34x35}+\frac{1}{35.36}\right)\)
\(A=9\left(\frac{5-4}{4x5}+\frac{6-5}{5x6}+\frac{7-6}{6x7}+...+\frac{35-34}{34x35}+\frac{36-35}{35x36}\right)\)
\(A=9\left(\frac{1}{4}-\frac{1}{36}\right)=9x\frac{8}{36}=2\)
NN
1
PT
0
MN
2 tháng 4 2020
\(\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}\)
\(=\frac{3-2}{2\times3}+\frac{4-3}{3\times4}+\frac{5-4}{4\times5}+\frac{6-5}{5\times6}\)
\(=\frac{3}{2\times3}-\frac{2}{2\times3}+\frac{4}{3\times4}-\frac{3}{3\times4}+\frac{5}{4\times5}-\frac{4}{4\times5}+\frac{6}{5\times6}-\frac{5}{5\times6}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{2}-\frac{1}{6}\)
\(=\frac{1}{3}\)
2 tháng 8 2016
\(\frac{3}{4.5}+\frac{3}{5.6}+\frac{3}{6.7}+.....+\frac{2}{19.20}\)
\(=3.\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+....+\frac{1}{19.20}\right)\)
\(=3.\left(\frac{1}{4}-\frac{1}{20}\right)\)
\(=3.\frac{1}{5}=\frac{3}{5}\)
9 tháng 9 2017
\(A=\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{7.8}\)
\(\Rightarrow5A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{7.8}\)
\(\Rightarrow5A=1.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...-\frac{1}{8}\right)\)
\(\Rightarrow5A=1-\frac{1}{8}\)
\(\Rightarrow A=\left(1-\frac{1}{8}\right).\frac{1}{5}=\frac{7}{40}\)
Q
9 tháng 9 2017
\(A=\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{7.8}\)
\(A=5\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{5}{7.8}\right)\)
\(A=5\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{8}\right)\)
\(A=5\left(1-\frac{1}{8}\right)\)
\(A=5.\frac{7}{8}\)
\(A=\frac{38}{8}\)
TT
4
\(\frac{9}{4.5}+\frac{9}{5.6}+...+\frac{9}{35.36}\)
\(9.\left(\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{35.36}\right)\)
\(9.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{35}-\frac{1}{36}\right)\)
\(9.\left(\frac{1}{4}-\frac{1}{36}\right)\)
\(9.\frac{2}{9}\)
\(=2\)