Question

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Answer 1

[Đỗ Tuệ Lâm]

Câu 4:

\(\%m_{MgCl_2}=\dfrac{0,3.95.100\%}{79,3}=35,94\%,\%m_{FeCl_2}=100\%-35,94\%=64,06\%,\)

2) \(\%m_{Al}=\dfrac{0,2.27.100\%}{16,2}=33,33\%\\ \%m_{Ag}=100\%-33,33=66,67\%\)

3) \(n_{HCl}=0,5.0,5=0,25;n_{H_2SO_4}=0,2.0,5=0,1\left(mol\right)\)

\(\%m_{HCl}=\dfrac{0,25.36,5.100\%}{0,25.36,5+0,1.98}=48,22\%\\ \%m_{H_2SO_4}=100\%-48,22\%=51,78\%\)

4)

\(n_{NaCl}=0,2.0,8=0,16\left(mol\right),n_{NaNO_3}=0,5.0,8=0,4\left(mol\right)\Rightarrow\%m_{NaCl}=\dfrac{0,16.58,5.100\%}{0,16.58,5+0,4.85}=21,59\%\Rightarrow\%m_{NaNO_3}=100\%-21,59\%=78,41\%\)