67 -7 x (2 + x) + 8 =40
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1) x-(-6)=8
x=8+(-6)
x= 2
(-5)+(x-1)=-2
x-1 = (-2)-(-5)
x-1 = 3
x=3+1
x=4
8-(x+8)=(-16)-(-26)
8-(x+8)= 10
x+8 =8-10
x+8 =-2
x=(-2)-8
x= -10
2)
-(67+37)-(67+23)
=(-67)-37-67-23
= (-104)-67-23
= (-171)-23
= -194
(-15+21)-(-38)+(15-38)
=(-15)+21-(-38)+15-38
=(-15+15)+21+38-38
= 0 +(38-38)+21
= 0 +0 +21
= 0 +21+15
= 21
\(0,25\times1,25\times8\times40+3,5\times67+3,5\times31+7\times1\)
\(=\left(0,25\times40\right)\times\left(1,25\times8\right)+3,5\times\left(67+31\right)+7\)
\(=10\times10+3,5\times98+7\)
\(=100+343+7\)
\(=450\)
\(\dfrac{11}{8}:x-\dfrac{2}{5}+-\dfrac{1}{6}=-\dfrac{1}{5}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}-\left(-\dfrac{1}{6}\right)\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}+\dfrac{1}{6}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{6}{30}+\dfrac{5}{30}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{30}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{2}{5}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{12}{30}\\ =>\dfrac{11}{8}:x=\dfrac{11}{30}\\ =>x=\dfrac{11}{8}:\dfrac{11}{30}\\ =>x=\dfrac{11}{8}.\dfrac{30}{11}\\ =>x=\dfrac{30}{8}\\ =>x=\dfrac{15}{4}\\ \dfrac{4}{7}x-\dfrac{1}{3}x+\left(-\dfrac{16}{21}\right)=-\dfrac{2}{3}\\ =>\left(\dfrac{4}{7}-\dfrac{1}{3}\right)x=-\dfrac{2}{3}-\left(-\dfrac{16}{21}\right)\\ =>\left(\dfrac{12}{21}-\dfrac{7}{21}\right)x=-\dfrac{2}{3}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=-\dfrac{14}{21}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=\dfrac{2}{21}\\ =>x=\dfrac{2}{21}:\dfrac{5}{21}\)
\(=>x=\dfrac{2}{21}.\dfrac{21}{5}\\ =>x=\dfrac{2}{5}\\ -\dfrac{11}{12}x+\dfrac{15}{2}\left(x+-\dfrac{1}{5}\right)=\dfrac{67}{8}\\ =>-\dfrac{11}{12}x+\dfrac{15}{2}.x-\dfrac{1}{5}=\dfrac{67}{8}\\ =>\left(-\dfrac{11}{12}+\dfrac{15}{2}\right)x=\dfrac{67}{8}+\dfrac{1}{5}\\ =>\left(-\dfrac{11}{12}+\dfrac{90}{12}\right)x=\dfrac{335}{40}+\dfrac{8}{40}\\ =>\dfrac{79}{12}x=\dfrac{343}{40}\\ =>x=\dfrac{343}{40}:\dfrac{79}{12}\\ =>x=\dfrac{343}{40}.\dfrac{12}{79}\\ =>x=\dfrac{343.12}{40.79}\\ =>x=\dfrac{343.3}{10.79}\\ =>x=\dfrac{1029}{790}\)
8 x 2 = 16 8 x 4 = 32 8 x 7 = 56 8 x 5 = 40
16 : 8 = 2 32 : 8 = 4 56 : 8 = 7 40 : 8 = 5
16 : 2 = 8 32 : 4 = 8 56 : 7 = 8 40 : 5 = 8
8 x 2 = 16 8 x 4 =32 8 x 7 =56 . 8 x 5 =40
16 : 8 = 2 32 : 8 =4 56 : 8 =7 40 : 8 =5
16 : 2 = 8 32 : 4 = 8 56 : 7 = 8 40 : 5 = 8
cái bài này bạn thuộc phép nhân chia của nó là làm dễ lắm nha
Bài 1:
$10+3(x-6)=5^{10}:5^8=5^2=25$
$3(x-6)=25-10=15$
$x-6=15:3=5$
$x=5+6=11$
Bài 2:
a. $100-[150-8(7-4)^2]=100-(150-8.3^2)=100-150+8.3^2$
$=-50+72=72-50=22$
b. $=-999-23+999-10-67=(-999+999)-10-(67+23)$
$=0-10-90=-(10+90)=-100$
a) Ta có: \(\dfrac{-11}{15}< \dfrac{x}{15}< \dfrac{-8}{15}\)
nên -11<x<-8
hay \(x\in\left\{-10;-9\right\}\)
b) Ta có: \(\dfrac{3}{7}< \dfrac{x}{21}< \dfrac{2}{3}\)
\(\Leftrightarrow\dfrac{9}{21}< \dfrac{x}{21}< \dfrac{14}{21}\)
Suy ra: 9<x<14
hay \(x\in\left\{10;11;12;13\right\}\)
c) Ta có: \(\dfrac{-67}{21}< \dfrac{x}{168}< \dfrac{-3}{8}\)
nên \(\dfrac{-536}{168}< \dfrac{x}{168}< \dfrac{-63}{168}\)
Suy ra: -536<x<-63
hay \(x\in\left\{-535;-534;...;-64\right\}\)
67 - 7 x (2+x) + 8 = 40
60 x (2+x) + 8 = 40
(2+x) +8 = 60: 40
(2+x) +8 = 20
2+x = 12
x = 12-2
x =10
đề sai hay sao ý