bài 1)tính bằng cách thuận tiện A,6/4+6/28+6/70+6/130+6/208 B,0,7x430x2+1,4x570+200
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1/2A=1/2(6/4+6/28+6/70+6/130+6/208)
= 3/4+3/28+3/70+3/130+3/208
= 1-1/4+1/4-1/7+..................-1/16
=1-1/16
=15/16 => A=15/8
A=\(\frac{6}{4}+\frac{6}{28}+\frac{6}{70}+\frac{6}{130}+\frac{6}{208}\)
A=\(\frac{6}{1\cdot4}+\frac{6}{4\cdot7}+\frac{6}{7\cdot10}+\frac{6}{10\cdot13}+\frac{6}{13\cdot16}\)
A:2=\(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}+\frac{3}{13\cdot16}\)
A:2=\(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\)\(\frac{1}{16}\)
A:2=\(1-\frac{1}{16}\)
A:2=\(\frac{15}{16}\)
A=\(\frac{15}{8}\)
vậy ...
a: Số số hạng là:
(24-2):2+1=12(số)
Tổng là:
\(\dfrac{26\cdot12}{2}=26\cdot6=156\)
a) 62389 + 4402 - 20389
= (62389 - 20389) + 4402
= 42000 + 4402
= 46402
b) 83268 + 15739 + 16732
=(83268 + 16732) + 15739
= 100 000 + 15 739
= 115 739
c) 30 + 35 + 40 + 45 + 50 + 55 + 60 + 65 + 70
=(30 + 70) + (35 + 65) + (40 + 60) + (45 + 55) + 50
= 100 + 100 + 100 + 100 + 50
= 100 x 4 + 50
= 400 + 50 = 450
\(\dfrac{7}{6}\times\dfrac{3}{4}+\dfrac{3}{4}\times\dfrac{5}{6}-\dfrac{3}{4}\\ =\left(\dfrac{7}{6}+\dfrac{5}{6}-1\right)\times\dfrac{3}{4}\\ =1\times\dfrac{3}{4}=\dfrac{3}{4}\\ \dfrac{6\times7\times15\times8}{4\times21\times10\times3}\\ =\dfrac{2\times3\times7\times5\times3\times4\times2}{4\times7\times3\times5\times2\times3}\\ =2\)
a: \(\dfrac{6}{4}+\dfrac{6}{28}+\dfrac{6}{70}+\dfrac{6}{130}+\dfrac{6}{208}\)
\(=2\left(\dfrac{3}{1\text{x}4}+\dfrac{3}{4\text{x}7}+\dfrac{3}{7\text{x}10}+\dfrac{3}{10\text{x}13}+\dfrac{3}{13\text{x}16}\right)\)
\(=2\text{x}\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{16}\right)\)
\(=2\text{x}\left(1-\dfrac{1}{16}\right)=2\text{x}\dfrac{15}{16}=\dfrac{15}{8}\)
b: \(0,7\text{x}430\text{x}2+1,4\text{x}570+200\)
\(=1,4\text{x}430+1,4\text{x}570+200\)
\(=1,4\text{x}\left(430+570\right)+200\)
=1400+200
=1600
\(a,\dfrac{6}{4}+\dfrac{6}{28}+\dfrac{6}{70}+\dfrac{6}{130}+\dfrac{6}{208}\)
\(=\dfrac{6}{1.4}+\dfrac{6}{4.7}+\dfrac{6}{7.10}+\dfrac{6}{10.13}+\dfrac{6}{13.16}\)
\(=2.\left(\dfrac{1}{1.4}+\dfrac{1}{4.7}+\dfrac{1}{7.10}+\dfrac{1}{10.13}+\dfrac{1}{13.16}\right)\)
\(=2.\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{16}\right)\)
\(=2.\left(1-\dfrac{1}{16}\right)\)
\(=2.\dfrac{15}{16}=\dfrac{15}{8}=1,875\)
\(b,0,7\times430\times2+1,4\times570+200\)
\(=1,4\times430+1,4\times570+200\)
\(=1,4\times\left(430+570\right)+200\)
\(=1,4\times1000+200\)
\(=1400+200=1600\)